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javascript - 根据 {liked :true} 、距离然后按 avg_rating 对数组对象进行多重排序

问题描述

我有一个数组对象如下

arr = [ {distance:4, avg_rating: 5}, 
        {distance: 6, avg_rating: 4}, 
        {distance: 7, avg_rating: 2, liked: true}, 
        {distance: 6, avg_rating: 4 , liked: true}, 
        {distance: 6, avg_rating: 3 , liked: true},
        {distance: 4, avg_rating: 3}]

我希望首先得到 {liked: true} 然后它会按距离升序排序，如果距离相同，那么它将根据 avg_rating 排序。

我使用了不工作的 javascript 排序方法。

arr.sort(function(a, b){                                     
      if (b.liked)  return  1;
      if(!b.liked) return -1;
      if (a.distance < b.distance) return 1;
      if (a.distance > b.distance) return -1;
      if (a.avg_rating < b.avg_rating) return -1;
      if (a.avg_rating > b.avg_rating) return 1;
 })

我希望结果是

arr = [{distance: 6, avg_rating: 4 , liked: true},
       {distance: 6, avg_rating: 3 , liked: true}
       {distance: 7, avg_rating: 2, liked: true},
       {distance: 4, avg_rating: 5},
       {distance: 4, avg_rating: 3},
       {distance: 6, avg_rating: 4}]

因此，首先所有 { like : true } 都在顶部并按距离按升序排序（即所有附近都在数组顶部），然后如果距离相同，则按 avg_rating 按降序排序（即所有相同的距离值是再次按 avg_rating 排序）

标签： javascriptnode.jssorting

解决方案

您可以通过获取每个项目的增量来链接所有条件并获得所需的订单。

对于第一对，取一个逻辑 NOT!以获得一个布尔值进行减法。

其他的按照排序的顺序，a - b（asc）和b - a（desc）。

var array = [{ distance: 4, avg_rating: 5 }, { distance: 6, avg_rating: 4 }, { distance: 7, avg_rating: 2, liked: true }, { distance: 6, avg_rating: 4, liked: true }, { distance: 6, avg_rating: 3, liked: true }, { distance: 4, avg_rating: 3 }];

array.sort((a, b) =>
    !a.liked - !b.liked ||
     a.distance - b.distance ||
     b.avg_rating - a.avg_rating
);

console.log(array);
.as-console-wrapper { max-height: 100% !important; top: 0; }

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