首页 > 解决方案 > Pandas - 在子集数据帧上调用用户定义的函数

问题描述

我正在 Pandas DataFrame 的子集上创建一个计数函数,并打算导出仅包含 groupby 标准和计数结果的字典/电子表格数据。

In [1]: df = pd.DataFrame([[Buy, A, 123, NEW, 500, 20190101-09:00:00am], [Buy, A, 124, CXL, 500, 20190101-09:00:01am], [Buy, A, 125, NEW, 500, 20190101-09:00:03am], [Buy, A, 126, REPLACE, 300, 20190101-09:00:10am], [Buy, B, 210, NEW, 1000, 20190101-09:10:00am], [Sell, B, 345, NEW, 200, 20190101-09:00:00am], [Sell, C, 412, NEW, 100, 20190101-09:00:00am], [Sell, C, 413, NEW, 200, 20190101-09:01:00am], [Sell, C, 414, CXL, 50, 20190101-09:02:00am]], columns=['side', 'sender', 'id', 'type', ''quantity', 'receive_time'])
Out[1]: 
   side  sender  id    type     quantity  receive_time 
0  Buy   A       123   NEW      500       20190101-09:00:00am
1  Buy   A       124   CXL      500       20190101-09:00:01am
2  Buy   A       125   NEW      500       20190101-09:00:03am
3  Buy   A       126   REPLACE  300       20190101-09:00:10am
4  Buy   B       210   NEW      1000      20190101-09:10:00am
5  Buy   B       345   NEW      200       20190101-09:00:00am
6  Sell  C       412   NEW      100       20190101-09:00:00am
7  Sell  C       413   NEW      200       20190101-09:01:00am
8  Sell  C       414   CXL      50        20190101-09:02:00am

计数函数如下(mydf 作为数据帧的子集传入):

def ordercount(mydf):
   num = 0.0
   if mydf.type == 'NEW':
      num = num + mydf.qty
   elif mydf.type == 'REPLACE':
      num = mydf.qty
   elif mydf.type == 'CXL':
      num = num - mydf.qty
   else: 
      pass
   orderdict = dict.fromkeys([mydf.side, mydf.sender, mydf.id], num)
   return orderdict

从 csv 读取数据后,我按一些标准对其进行分组并按时间排序:

df = pd.read_csv('xxxxxxxxx.csv, sep='|', header=0, engine='python', names=col_names)
sorted_df = df.groupby(['side', 'sender', 'id']).apply(lambda_df:_df.sort_values(by=['time']))

然后对排序后的数据调用之前定义的函数:

print(sorted_df.agg(ordercount))

但是值错误不断上升,说要调用的行太多。

统计数据的函数方式可能效率不高,但它是我能想到的最直接的方式来匹配订单类型和相应的统计数量。我希望程序输出一个表,其中只显示边、发件人、ID 和计数的数量。有什么办法可以做到这一点?谢谢。

预期输出:

   side   sender   total_order_num   trade_date 
0  Buy    A        300               20190101
1  Buy    B        1200              20190101
2  Sell   C        250               20190101

标签: pythonpandasfunctiondataframepandas-groupby

解决方案


我相信您的功能不容易一次应用,因为您根据行执行不同的操作。如果您只拥有+-作为您的操作,但您replace在某个时候获得了价值,然后继续进行其他操作,这将是可以的。因此,循环可能会更简单,或者您可以花一些时间来拥有一个很好的函数来完成任务。

这就是我所拥有的。我真正做的只是改变你的ordercount,让它直接在一个子集上运行,你可以通过简单的分组来获得。您可以在分组之前按时间排序,也可以在ordercount函数中进行排序。希望这会有所帮助。

import pandas as pd
df = pd.DataFrame([['Buy', 'A', 123, 'NEW', 500, '20190101-09:00:00am'],
                   ['Buy', 'A', 124, 'CXL', 500, '20190101-09:00:01am'],
                   ['Buy', 'A', 125, 'NEW', 500, '20190101-09:00:03am'],
                   ['Buy', 'A', 126, 'REPLACE', 300, '20190101-09:00:10am'],
                   ['Buy', 'B', 210, 'NEW', 1000, '20190101-09:10:00am'],
                   ['Buy', 'B', 345, 'NEW', 200, '20190101-09:00:00am'],
                   ['Sell', 'C', 412, 'NEW', 100, '20190101-09:00:00am'],
                   ['Sell', 'C', 413, 'NEW', 200, '20190101-09:01:00am'],
                   ['Sell', 'C', 414, 'CXL', 50, '20190101-09:02:00am']],
columns=['side', 'sender', 'id', 'type', 'quantity', 'receive_time'])

df['receive_time'] = pd.to_datetime(df['receive_time'])
df['receive_date'] = df['receive_time'].dt.date # you do not need the time stamps


def ordercount(mydf):
    mydf_ = mydf.sort_values('receive_time')[['type', 'quantity']].copy()
    num = 0
    for val in mydf_.values:
        type_, quantity = val
        # val is going to be a list like ['NEW', 500]. All I am doing above is unpack the list into two variables.
        # You can find many resources on unpacking iterables
        if type_ == 'NEW':
            num += quantity
        elif type_ == 'REPLACE':
            num = quantity
        elif type_ == 'CXL':
            num -= quantity
        else:
            pass
    return num

mydf = df.groupby(['side', 'sender', 'receive_date']).apply(ordercount).reset_index()

输出:

|----|--------|----------|---------------------|------|
|    | side   | sender   | receive_date        |    0 |
|----|--------|----------|---------------------|------|
|  0 | Buy    | A        | 2019-01-01 00:00:00 |  300 |
|----|--------|----------|---------------------|------|
|  1 | Buy    | B        | 2019-01-01 00:00:00 | 1200 |
|----|--------|----------|---------------------|------|
|  2 | Sell   | C        | 2019-01-01 00:00:00 |  250 |
|----|--------|----------|---------------------|------|

您可以根据需要轻松重命名列“0”。我仍然不确定你trade_date是如何定义的。您的数据是否只有一个日期?当你有多个约会对象时会发生什么?你是在取款吗?...

编辑:如果您尝试使用此数据框,您可以看到日期按预期工作的组。

df = pd.DataFrame([['Buy', 'A', 123, 'NEW', 500, '20190101-09:00:00am'],
                   ['Buy', 'A', 124, 'CXL', 500, '20190101-09:00:01am'],
                   ['Buy', 'A', 125, 'NEW', 500, '20190101-09:00:03am'],
                   ['Buy', 'A', 126, 'REPLACE', 300, '20190101-09:00:10am'],
                   ['Buy', 'B', 210, 'NEW', 1000, '20190101-09:10:00am'],
                   ['Buy', 'B', 345, 'NEW', 200, '20190101-09:00:00am'],
                   ['Sell', 'C', 412, 'NEW', 100, '20190101-09:00:00am'],
                   ['Sell', 'C', 413, 'NEW', 200, '20190101-09:01:00am'],
                   ['Sell', 'C', 414, 'CXL', 50, '20190101-09:02:00am'],
                   ['Buy', 'A', 123, 'NEW', 500, '20190102-09:00:00am'],
                   ['Buy', 'A', 124, 'CXL', 500, '20190102-09:00:01am'],
                   ['Buy', 'A', 125, 'NEW', 500, '20190102-09:00:03am'],
                   ['Buy', 'A', 126, 'REPLACE', 300, '20190102-09:00:10am'],
                   ['Buy', 'B', 210, 'NEW', 1000, '20190102-09:10:00am'],
                   ['Buy', 'B', 345, 'NEW', 200, '20190102-09:00:00am'],
                   ['Sell', 'C', 412, 'NEW', 100, '20190102-09:00:00am'],
                   ['Sell', 'C', 413, 'NEW', 200, '20190102-09:01:00am'],
                   ['Sell', 'C', 414, 'CXL', 50, '20190102-09:02:00am']],
columns=['side', 'sender', 'id', 'type', 'quantity', 'receive_time'])

推荐阅读