php - 使用 PHP 从复杂的 JSON 有效负载中获取所有键值对
问题描述
我有一个从服务器收到的 JSON 文件,它不能在任何时候更改。我正在尝试key:value
使用 PHP 取出所有配对,但我的成功是部分的。
有没有人因为我找不到任何答案而处理这种麻烦?
如您所见,我做了一些编码
<?php
$content = ('{
"app_id": "test1",
"dev_id": "temperature",
"hardware_serial": "0056748F03A5C6CB1",
"port": 1,
"counter": 2217,
"payload_raw": "AYgAAAAAAAAAAAA=",
"payload_fields": {
"height": 0,
"pressure": 0,
"temperature": 3.92
},
"metadata": {
"time": "2019-07-16T20:39:37.761000811Z",
"frequency": 867.9,
"modulation": "LORA",
"data_rate": "SF7BW125",
"coding_rate": "4/5",
"gateways": [
{
"gtw_id": "eui-b346ebfffec332dc",
"timestamp": 2514820708,
"time": "2019-07-16T20:39:37.735765Z",
"channel": 7,
"rssi": -65,
"snr": 9.5,
"rf_chain": 0,
"latitude": 44.754036,
"longitude": 19.690582,
"location_source": "registry"
}
]
},
"downlink_url": "https://integrations.net"}');
$mypayload = json_decode($content, true);
//decode and save JSON data
$AppID = $mypayload['app_id'];
$DevID = $mypayload['dev_id'];
$HardwareSerial = $mypayload['hardware_serial'];
$Counter = $mypayload['counter'];
$PayloadRaw = $mypayload['payload_raw'];
$PayloadFields = $mypayload['payload_field'];
$Time = $mypayload['metadata']['time'];
$DataRate = $mypayload['metadata']['data_rate'];
$CodingRate = $mypayload['metadata']['coding_rate'];
$GtwID = $mypayload['gtw_id'];
$GwTime = $mypayload['gateways']['time'];
$GwRssi = $mypayload['gateways']['rssi'];
$GwSnr = $mypayload['gateways']['snr'];
$GwLatitude = $mypayload['gateways']['latitude'];
$GwLongitude = $mypayload['gateways']['longitude'];
$myfile = fopen("C:/Users/Public/Documents/test2.txt","a+") or die("Unable to open file!");
fwrite($myfile, "App ID = " . $AppID . "\n" );
fwrite($myfile, "DevID = " . $DevID . "\n" );
fwrite($myfile, "HardwareSerial = " . $HardwareSerial . "\n" );
fwrite($myfile, "Counter = " . $Counter . "\n" );
fwrite($myfile, "PayloadRaw = " . $PayloadRaw . "\n" );
fwrite($myfile, "PayloadFields = " . $PayloadFields . "\n" );
fwrite($myfile, "Time = " . $Time . "\n");
fwrite($myfile, "DataRate = " . $DataRate . "\n" );
fwrite($myfile, "CodingRate = " . $CodingRate . "\n" );
fwrite($myfile, "GtwID = " . $GtwID . "\n");
fwrite($myfile, "GwTime = " . $GwTime . "\n");
fwrite($myfile, "GwRssi = " . $GwRssi . "\n");
fwrite($myfile, "GwSnr = " . $GwSnr . "\n");
fwrite($myfile, "GwLatitude = " . $GwLatitude . "\n" );
fwrite($myfile, "GwLongitude = " . $GwLongitude . "\n" );
fwrite($myfile, "test1 = " . $test1 . "\n" );
fclose($myfile);
?>
我知道为什么我会收到这个错误,但我显然无法用我对 PHP 的了解来解决它:)
注意:未定义索引:第 49 行 E:\xampp7\htdocs\test\test.php 中的 payload_field
注意:未定义的索引:第 53 行 E:\xampp7\htdocs\test\test.php 中的 gtw_id
注意:未定义索引:第 54 行 E:\xampp7\htdocs\test\test.php 中的网关
注意:未定义索引:第 55 行 E:\xampp7\htdocs\test\test.php 中的网关
注意:未定义索引:第 56 行 E:\xampp7\htdocs\test\test.php 中的网关
注意:未定义索引:第 57 行 E:\xampp7\htdocs\test\test.php 中的网关
注意:未定义索引:第 58 行 E:\xampp7\htdocs\test\test.php 中的网关
注意:未定义变量:第 78 行 E:\xampp7\htdocs\test\test.php 中的 test1
所以我需要帮助。提前致谢。
解决方案
有几个错误:
- 索引必须
payload_fields
是payload_field
- 它必须
$mypayload["metadata"]["gateways"]["gtw_id"]
代替$mypayload["gtw_id"]
- 它必须
$mypayload["metadata"]["gateways"]
代替$mypayload["gateways"]
等等。
请再次检查您的json。
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