python - 从 num_dict 返回值大于或等于 min_cutoff 的所有键（按设置）

Question

参数

num_dict: dictionary
  all values are numeric
min_cutoff: float

与num_dict值进行比较。返回其值 >= min_cutoff 的所有键。

我的字典是{'Denver': 200, 'Houston': 100, 'NOLA':50}

def keys_get_cutoff(num_dict, min_cutoff):
    for k, v in num_dict.items():
        if v >= min_cutoff:
            print(keys_get_cutoff(num_dict, min_cutoff))

标签： pythondictionary

Answer 1

def keys_get_cutoff(dict, min_value):

    return [key for key in dict.keys() if dict[key] >= min_value]