python - 在“if/elif/else”语句中调用了不正确的代码

Question

我正在制作一个计算复利和单利的利息计算器。但是，无论输入如何，if 语句始终运行单利脚本。

我尝试将变量更改为字符串、整数和浮点数。我试过改变变量名，我试过完全删除第一块代码。它到底有什么问题？？？

start = input("simple or compound: ")

if start == "simple" or "Simple":
    a = float(input('Starting balance: '))
    b = float(input('Rate: '))
    c = int(input('Years: '))

    final = int(a+((a*b*c)/100))
    print(final)
elif start == "compound" or "Compound":
    d = float(input('Starting balance: '))
    e = float(input('Rate: '))
    f = int(input('Years: '))

    final2 = int(d*(1+(e/100))**f)
    print(final2)
else:
    d = float(input('Starting balance: '))
    e = float(input('Rate: '))
    f = int(input('Years: '))

    final3 = int(d*(1+(e/100))**f)
    print(final3)

如果我输入起始余额为 5000，利率为 5，年数为六，简单的输入为 6500。但当我调用复合时，会出现相同的结果。

标签： pythonboolean

Answer 1

这个表达式不正确：

start == "simple" or "Simple"

应该

start == "simple" or start "Simple"

下面的代码有效：

start = input("simple or compound: ")

if start == "simple" or start == "Simple":
    # print("simple")
    a = float(input('Starting balance: '))
    b = float(input('Rate: '))
    c = int(input('Years: '))

    final = int(a+((a*b*c)/100))
    print(final)
elif start == "compound" or start == "Compound":
    # print("compound")
    d = float(input('Starting balance: '))
    e = float(input('Rate: '))
    f = int(input('Years: '))

    final2 = int(d*(1+(e/100))**f)
    print(final2)
else:
    # print("unknown")
    d = float(input('Starting balance: '))
    e = float(input('Rate: '))
    f = int(input('Years: '))

    final3 = int(d*(1+(e/100))**f)
    print(final3)