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java - Java Socket 服务器在读取数据时挂起

问题描述

我有一个与 Java 套接字服务器通信的 PHP 文件，当我发送数据时，我的 Java 服务器卡住（挂起、冻结）在inputLine = in.readLine(). 我调试过，发现只有当我读取数据时，才会出现这种情况。

这是我的服务器java方法：

public void start_echo_server(int port){
    main.getProxy().getConsole().sendMessage(new TextComponent(ChatColor.GOLD + "STARTING SOCKET LISTENER (echo)"));

    int portNumber = port;
    try {
        ServerSocket serverSocket = new ServerSocket(portNumber);
        Socket clientSocket = serverSocket.accept();
        // accepted the connection
        main.getProxy().getConsole().sendMessage(new TextComponent(ChatColor.GOLD + "ACCEPTED"));
        // in stream
        BufferedReader in = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));
        // outstream
        PrintWriter out = new PrintWriter(clientSocket.getOutputStream(), true);

        String inputLine;
        StringBuilder sb = new StringBuilder();
        while ((inputLine = in.readLine()) != null) {
            sb.append(inputLine);
        }
        String final_line = sb.toString();
        main.getProxy().getConsole().sendMessage(new TextComponent(ChatColor.GOLD + "IN: " + final_line));
        //String final_ret = parser.parse_message(final_line);
        //main.getProxy().getConsole().sendMessage(new TextComponent(ChatColor.GOLD + "FINAL: " + final_ret));
        out.println(final_line);
        in.close();
        out.close();
        serverSocket.close();
    } catch (IOException e) {
        e.printStackTrace();
    }
}

这是我的 PHP 文件：

    <?php
  if( isset($_POST['username']) )
  {
     $username = $_POST['username'];
     parse($username);
  }else{
    echo "Missing parameters!";
    exit();
  }
  function parse($username){
    //Must be same with server
    $host = "127.0.0.1";
    $port = 59090;
    // No Timeout
    //Create Socket
    $sock = socket_create(AF_INET, SOCK_STREAM, 0) or die("Could not create socket\n");
    //Connect to the server
    $result = socket_connect($sock, $host, $port) or die("Could not connect toserver\n");
    $message = "player_online ". $username;
    //Write to server socket
    $len = strlen($message);

    socket_write($sock, $message, $len) or die("SENDING ERROR ". $message ." \n");
    //Read server respond message
    $result = socket_read($sock, 1024) or die("RESPONSE ERROR ". $message ." \n");
    echo "Reply From Server  :".$result;
    //Close the socket
    socket_close($sock);
  }
?>

问题是当我socket_write在 PHP 端执行（写入数据）时，但问题出在 java 行while ((inputLine = in.readLine()) != null) {。

非常感谢！

标签： javaphpsocketsfreeze

解决方案

解决了！

我正在阅读多行，只有一行进入，而我没有\n在消息之后包含换行符 ( )（这表示上一条消息是已完成的一行）。将 PHP 替换$message = "player_online ". $username;为$message = "player_online ". $username ."\n";

还不得不更换Java

String inputLine;
StringBuilder sb = new StringBuilder();
while ((inputLine = in.readLine()) != null) {
    sb.append(inputLine);
}
String final_line = sb.toString();

和

String inputLine = in.readLine();
String final_line = inputLine;

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