c# - 每次按下按钮时，如何按顺序保存旧的数字变量？

Question

我试图从随机数生成器中排除旧结果，但我似乎无法让变量记住过去的两个。我是 C# 新手，所以我可能忽略了一些非常简单的解决方案。如果你们能启发我，那将是非常有帮助的。

我已经尝试过下面显示的代码，我很确定我很愚蠢，但我不知道为什么它不起作用。

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Timers;
using System.Threading.Tasks;
using System.IO;
using System.Windows.Forms;

namespace WindowsFormsApp1
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        private void label_click(object sender, EventArgs e)
        {
            Close();
        }

        int mouseX = 0, mouseY = 0;
        bool mouseDown;



        private void panel1_MouseDown(object sender, MouseEventArgs e)
        {
            mouseDown = true;
        }

        private void panel1_MouseUp(object sender, MouseEventArgs e)
        {
            mouseDown = false;
        }

        private void GOBUTN_Paint(object sender, PaintEventArgs e)
        {



        }
        //Sharing is caring: Communism goes here
        private System.Windows.Forms.Timer timtim;
        PictureBox Rooskie = new PictureBox();
        int duplicheck = 0;
        int duplicheck2 = 0;
        int duplicheck3 = 0;
        Label test = new Label();
        private void boopthesnoot(object sender, EventArgs e)
        {
            dinging:
            //yeah, random numbers here
            Random rando = new Random();
            int rand0 = rando.Next(1, 25);
            test.Text = duplicheck + ", " + duplicheck2 + ", " + duplicheck3;
            test.Font = new Font("Calibri", 20);
            Controls.Add(test);
            test.Location = new Point(0, 200);
            test.Height = 1000;
            test.Width = 1000;
            if(duplicheck != rand0 && duplicheck2 != rand0 && duplicheck3 != rand0)
            {
                GOBUTTON.Hide();
                pictureBox1.Hide();
                pictureBox2.Hide();

                //image code goes here
                string filepath = Environment.GetFolderPath(Environment.SpecialFolder.Desktop) + "\\" + "resources" + "\\" + rand0 + ".jpg";
                Rooskie.Width = 1160;
                Rooskie.Height = 620;
                Bitmap image = new Bitmap(filepath);
                Rooskie.Dock = DockStyle.Fill;
                Rooskie.Image = (Image)image;
                Controls.Add(Rooskie);
                Rooskie.SizeMode = PictureBoxSizeMode.CenterImage;


                //Aww, it's that timer time
                timtim = new System.Windows.Forms.Timer();
                timtim.Tick += new EventHandler(clockfinish);
                timtim.Interval = 5000;
                timtim.Start();
            }
            else
            {
                goto dinging;
            }

            if (duplicheck != rand0)
            {
                duplicheck2 = duplicheck;
            }

            if(duplicheck != rand0)
            {
                duplicheck2 = duplicheck;
            }

            if (duplicheck2 != duplicheck)
            {
                duplicheck3 = duplicheck2;
            }

            duplicheck = rand0;

        }

        private void clockfinish(object sender, EventArgs e)
        {
            //CEASE THE TIMER AND GIVE ME BACK MY BUTTON
            Rooskie.Image = null;
            timtim.Stop();
            GOBUTTON.Show();
            pictureBox1.Show();
            pictureBox2.Show();
        }

这个想法是随机数生成器选择图像并显示它。但我不希望同一图像连续显示多次，所以这应该给它一个缓冲区，即如果第一次按下按钮时显示图像 2，则图像 1 显示在第二个按钮上，图像 3 是显示在第三个，结果应该是这样的： duplicheck = 2 duplicheck2 = 1 duplicheck3 = 3

标签： c#

Answer 1

因此，在评论中每个人的帮助和大量的混乱下，我最终解决了这个问题。它可以完美地防止任何图像在每 25 次单击按钮时显示超过一次。非常感谢你们在这方面的帮助！如果没有你，我想我不会想到这一点。

//Sharing is caring: Communism goes here
        private System.Windows.Forms.Timer timtim;
        int rand0;
        PictureBox Rooskie = new PictureBox();
        Label test = new Label();
        Random rando = new Random();
        List<int> duplicheck = new List<int>();


        private void boopthesnoot(object sender, EventArgs e)
        {
        dingding:
            //yeah, random numbers here
            rand0 = rando.Next(1, 26);


            /*string combowombo = string.Join(", ", duplicheck.ToArray());
            test.Text = combowombo;
            test.Font = new Font("Calibri", 20);
            Controls.Add(test);
            test.Location = new Point(0, 200);
            test.Height = 1000;
            test.Width = 1000;*/
            if(duplicheck.Contains(rand0))
            {
                goto dingding;
            }
            else
            {
                GOBUTTON.Hide();
                pictureBox1.Hide();
                pictureBox2.Hide();

                //image code goes here
                Rooskie.Width = 1160;
                Rooskie.Height = 620;
                Bitmap image = new Bitmap(WindowsFormsApp1.Properties.Resources._1);
                Rooskie.Dock = DockStyle.Fill;
                Rooskie.Image = (Image)image;
                Controls.Add(Rooskie);
                Rooskie.SizeMode = PictureBoxSizeMode.CenterImage;


                //Aww, it's that timer time
                timtim = new System.Windows.Forms.Timer();
                timtim.Tick += new EventHandler(clockfinish);
                timtim.Interval = 3000;
                timtim.Start();
                duplicheck.Add(rand0);
                if (duplicheck.Count == 25)
                {
                    duplicheck = new List<int>();
                }
            }
        }