mysql - 我想在没有选择过滤器时返回所有带有计数的数据
问题描述
我正在创建一个商店,它将根据选定的过滤器运行,例如,当通过 studentid 时,它将返回所有数据以及记录数。当 schoolid 通过时,它会将所有数据返回到 schoolid 和记录数。同样,我希望在未选择任何过滤器时返回所有记录数的数据。目前它显示错误“#1064 - 您的 SQL 语法有错误;请查看与您的 MariaDB 服务器版本相对应的手册,以了解在 'ELSE 附近使用的正确语法
SELECT SQL_CALC_FOUND_ROWS DISTINCT map.idnstudent as Student_Count,ma' at line 21"。请帮我解决这个问题,我需要很多帮助。到目前为止,我已经尝试了所有可能的解决方案。
DROP PROCEDURE IF EXISTS `TestspPendingTab_filter_all123`;
DELIMITER $$
CREATE DEFINER=`root`@`localhost` PROCEDURE `TestspPendingTab_filter_all123`(IN `no_filter_data` VARCHAR(500), IN `search_keyword` VARCHAR(50), IN `Stud_id_filter` VARCHAR(100), IN `sch_id_filter` VARCHAR(100), IN `Subj_id_filter` VARCHAR(100), IN `start_date_filter` DATE, IN `end_date_filter` DATE, OUT `recordfound` INT(10))
BEGIN
CASE WHEN no_filter_data = 'YES' THEN
SELECT SQL_CALC_FOUND_ROWS DISTINCT
map.idnstudent as Student_Count,map.idnstudent as student_id,usr.name as student_name,
map.idnsubject as Subject_Count,map.idnsubject as subject_id,sn.sub_name as subject_name,
s.id as School_Count,s.id as school_id,ifnull(s.schoolname,'N/A') AS schoolname
from `user` `usr`
join `student_class_hour_map` `map` on `map`.`idnstudent`=`usr`.`id` and `usr`.`flag_status`=1
left join `subject_name` `sn` on `sn`.`id` = `map`.`idnsubject`
left join `school_student_rel` `ssrl` on `ssrl`.`student_id`=`map`.`idnstudent`
left join `school` `s` on `s`.`id` = `ssrl`.`school_id`
WHERE 1
AND map.archivestatus=0
AND recordfound = FOUND_ROWS()
ELSE
SELECT SQL_CALC_FOUND_ROWS DISTINCT
map.idnstudent as Student_Count,map.idnstudent as student_id,usr.name as student_name,
map.idnsubject as Subject_Count,map.idnsubject as subject_id,sn.sub_name as subject_name,
s.id as School_Count,s.id as school_id,ifnull(s.schoolname,'N/A') AS schoolname
from `user` `usr`
join `student_class_hour_map` `map` on `map`.`idnstudent`=`usr`.`id` and `usr`.`flag_status`=1
left join `subject_name` `sn` on `sn`.`id` = `map`.`idnsubject`
left join `school_student_rel` `ssrl` on `ssrl`.`student_id`=`map`.`idnstudent`
left join `school` `s` on `s`.`id` = `ssrl`.`school_id`
WHERE 1
AND map.archivestatus=0
AND
CASE WHEN search_keyword != '' THEN
(s.schoolname like CONCAT('%', search_keyword, '%') OR sn.sub_name like CONCAT('%', search_keyword, '%') OR usr.name like CONCAT('%', search_keyword, '%'))
ELSE
1
END
AND
CASE WHEN Stud_id_filter != '' THEN
FIND_IN_SET(map.idnstudent,Stud_id_filter)
ELSE 1
END
AND
CASE
WHEN sch_id_filter != '' THEN
FIND_IN_SET(s.id,sch_id_filter)
ELSE
1
END
AND
CASE
WHEN Subj_id_filter != '' THEN
FIND_IN_SET(map.idnsubject,Subj_id_filter)
ELSE
1
END
AND
CASE
WHEN start_date_filter != '' AND end_date_filter != '' THEN
map.startdate >= start_date_filter and map.enddate <= end_date_filter
ELSE
1
END
END
GROUP BY
CASE WHEN stud_id_filter <> '' THEN map.idnstudent END,
CASE WHEN sch_id_filter <> '' THEN s.id END,
CASE WHEN subj_id_filter <> '' THEN map.idnsubject END;
SET recordfound = FOUND_ROWS();
END$$
DELIMITER ;
预期输出:当没有选择过滤器时,它应该返回所有记录数的数据。如果选择了任何过滤器,则根据该过滤器返回数据以及记录数。
解决方案
在表单的存储过程代码中
CASE
WHEN something
THEN query1;
ELSE query2;
查询后需要分号。你没有它们。
您的代码有点令人困惑,因为您CASE
同时使用控制流和 SELECT 逻辑。这是需要分号的控制流/
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