首页 > 解决方案 > 在 terraform 中,如何将传入的变量用于地图?

问题描述

使用 terraform v0.12.3

$ terraform version
Terraform v0.12.3
+ provider.aws v2.20.0

我的 variables.tf 文件中有这个映射变量

variable "subnet_id" {
  type = map
  description = "Subnet to use"
  default = {
    sandbox = {
      us-east-1a = "subnet-1234"
      us-east-1b = "subnet-2345"
      us-east-1c = "subnet-3456"
      us-east-1d = ""
      us-east-1e = ""
      us-east-1f = ""
    }
    staging = {
      us-east-1a = "subnet-4567"
      us-east-1b = "subnet-5678"
      us-east-1c = "subnet-6789"
      us-east-1d = ""
      us-east-1e = ""
      us-east-1f = ""
    }
    production = {
      us-east-1a = "subnet-7890"
      us-east-1b = "subnet-0987"
      us-east-1c = "subnet-9876"
      us-east-1d = "subnet-8765"
      us-east-1e = "subnet-7654"
      us-east-1f = ""
    }
  }
}

如何通过传递环境变量来获取我想要的子网 ID?IOW,我想...

$ terraform plan -var 'environment=sandbox'

在我的 main.tf 代码中,我有

module "jenkins_slave" {
  subnet_id = var.subnet_id[var.environment["us-east-1a"]]
  ....
}

我明白了

$ terraform plan -var environment="sandbox"
Error: Invalid index

  on main.tf line 17, in module "jenkins-slaves":
  17:   subnet_id         = var.subnet_id[var.environment["us-east-1a"]]
    |----------------
    | var.environment is "sandbox"

This value does not have any indices.

就我而言,我希望subnet_idkey 最终等于subnet-1234

标签: terraformterraform-provider-aws

解决方案


首先,为了能够传递一个变量,你需要在你的代码中定义它:

variable "environment" {}

此外,var.subnet_id[var.environment["us-east-1a"]]您需要拥有var.subnet_id[var.environment]["us-east-1a"].

否则,var.environment["us-east-1a"]指的是地图的us-east-1a键。environment在您的情况下environment只是一个字符串而不是地图,因此 Terraform 会抛出一个错误:This value does not have any indices..

PS 看来,你也有错字variable "subnet_id" {...}ssandbox应该是sandbox


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