首页 > 解决方案 > 使用正则表达式提取字符串中的浮点数

问题描述

我有以下字符串列表

List = ['A = -25.47 dBm' , 'B = -47.35 dBm' , 'A = -26.54 dBm' , 'B = -32.35 dBm', 'A = 27.95 dBm' , 'B = -64.11 dBm' , 'A = -45.11 dBm' , 'B = -18.67 dBm']

我想提取 A 的值并列出 B 的值并列出

我试过以下

#First I joined the data into a string
S = ' '.join(List)
re.findall(r"A =  ([-+]?\d*\.\d+|\d+) dBm" , S)

这似乎不起作用

预期结果

A_list = [-25.47,-26.54, 27.95,-45.11] 
B_list = [-47.35,-32.35,-64.11,-18.67]

标签: pythonregex

解决方案


您可以使用recollections.defaultdict

import re, collections
l = ['A = -25.47 dBm' , 'B = -47.35 dBm' , 'A = -26.54 dBm' , 'B = -32.35 dBm', 'A = 27.95 dBm' , 'B = -64.11 dBm' , 'A = -45.11 dBm' , 'B = -18.67 dBm']
d = collections.defaultdict(list)
for i in l:
  a, b = re.findall('^\w+|[\-\d\.]+', i)
  d[a].append(float(b))

A_list, B_list = d['A'], d['B']

输出:

[-25.47, -26.54, 27.95, -45.11]
[-47.35, -32.35, -64.11, -18.67]

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