node.js - 如果此任务在此文件更改时启动，如何运行任务（更改文件）并避免循环

问题描述

我有任务：

将我的 Sass 代码编译成 css 的“样式”
.sass 文件更改时将启动“样式”的“watch”
启动所有任务的“默认”

一切都很好，直到我想对我的属性进行排序，我找到了可以在 CLI 中工作的 sass-sort 模块。我还下载了 gulp-exec 模块，所以我可以将命令添加sortsass ./src/styles/main.sass到我的任务中styles

我尝试.pipe(exec('sortsass ./src/styles/main.sass'))从“样式”中取出，创建新任务，并将其添加到“监视”任务中（因此在文件更改后，任务“样式”和新任务开始），结果相同。还尝试用谷歌搜索其他对 .sass 文件中的属性进行排序的方法（样式 lint 与 scss 配合得很好，但我正在使用 sass），试图找到vscode可以做到这一点的扩展。

    const gulp         = require('gulp');
    const browserSync  = require('browser-sync').create();
    const del          = require('del');
    const imagemin     = require('gulp-imagemin')
    const concat       = require('gulp-concat');
    const uglify       = require('gulp-uglify');
    const sourcemaps   = require('gulp-sourcemaps');
    const sass         = require('gulp-sass');
    const cleanCSS     = require('gulp-clean-css');
    const autoprefixer = require('gulp-autoprefixer');
    const exec         = require('gulp-exec');

    gulp.task('clean', function() {
      return del([
        'build/*']);
    });

    gulp.task('markup', function() {
      return gulp.src([
        './src/**/*.html'
      ],  {base: './src/'})
        .pipe(gulp.dest('./build/'))
        .pipe(browserSync.stream());
    });

    gulp.task('styles', function() {
      return gulp.src([
        './src/**/*.sass'
      ],  {base: './src/'}) 
        .pipe(exec('sortsass ./src/styles/main.sass'))
        .pipe(sourcemaps.init())
        .pipe(sass())
        .pipe(cleanCSS({level: 2}))
        .pipe(autoprefixer({Browserslist: ['last 2 versions'], cascade: false}))
        .pipe(sourcemaps.write('./'))
        .pipe(gulp.dest('./build/'))
        .pipe(browserSync.stream())
    });

    gulp.task('scripts', function() {
      return gulp.src([
        './src/js/lib.js',
        './src/js/main.js',
      ],  {base: './src/'})
        .pipe(uglify({toplevel: true}))
        .pipe(gulp.dest('./build/'))
        .pipe(browserSync.stream());
    });

    gulp.task('concat-scripts', function() {
      return gulp.src([
        './build/js/lib.js',
        './build/js/main.js',
      ])
        .pipe(concat('script.js'))
        .pipe(gulp.dest('./build/js/'))
        .pipe(browserSync.stream());
    })

      gulp.task('images', function() {
        return gulp.src([
          './src/img/**'
        ],  {base: './src/'})
          .pipe(imagemin({progressive: true}))
          .pipe(gulp.dest('./build/'))
          .pipe(browserSync.stream());
    });

    gulp.task('watch', function() {
      browserSync.init({
        server: {
            baseDir: "./build/"
        }
      });
      gulp.watch('./src/**/*.html', gulp.series('markup'))
      gulp.watch('./src/**/*.sass', gulp.series('styles'))
      gulp.watch('./src/**/*.js', gulp.series('scripts', 'concat-scripts'))
      gulp.watch('./src/**/img/**/*', gulp.series('images'))
    });

    gulp.task('trash', function() {
      return del([
        './build/styles/media.css',
        './build/styles/media.css.map',
        './build/js/lib.js',
        './build/js/main.js',
      ]);
    });

    gulp.task('default', gulp.series(gulp.series('clean',
                                   gulp.parallel('markup',
                                                 'images',
                                                 'styles',
                                                 'scripts')),
                                                 'concat-scripts',
                                                 'trash',
                                                 'watch'))

当我开始“默认”任务时：

    [19:35:15] Using gulpfile ~\Desktop\projects\new\gulpfile.js
    [19:35:15] Starting 'default'...
    [19:35:15] Starting 'clean'...
    [19:35:15] Finished 'clean' after 34 ms
    [19:35:15] Starting 'markup'...
    [19:35:15] Starting 'images'...
    [19:35:15] Starting 'styles'...
    [19:35:15] Starting 'scripts'...
    [19:35:15] gulp-imagemin: Minified 0 images
    [19:35:15] Finished 'images' after 58 ms
    [19:35:15] Finished 'markup' after 61 ms
    [19:35:15] Finished 'scripts' after 61 ms
    [19:35:15] Finished 'styles' after 239 ms
    [19:35:15] Starting 'concat-scripts'...
    [19:35:15] Finished 'concat-scripts' after 9.62 ms
    [19:35:15] Starting 'trash'...
    [19:35:15] Finished 'trash' after 5.4 ms
    [19:35:15] Starting 'watch'...
    [Browsersync] Access URLs:
     ------------------------------------
           Local: http://localhost:3000
        External: http://192.168.0.4:3000
     ------------------------------------
              UI: http://localhost:3001
     UI External: http://localhost:3001
     ------------------------------------
    [Browsersync] Serving files from: ./build/

and when I am changing sass file

    [19:36:46] Starting 'styles'...
    [Browsersync] 4 files changed (main.css.map, main.css, media.css.map, media.css)
    [19:36:47] Finished 'styles' after 264 ms
    [19:36:47] Starting 'styles'...
    [Browsersync] 4 files changed (main.css.map, main.css, media.css.map, media.css)
    [19:36:47] Finished 'styles' after 228 ms
    [19:36:47] Starting 'styles'...
    [Browsersync] 4 files changed (main.css.map, main.css, media.css.map, media.css)
    [19:36:48] Finished 'styles' after 223 ms
    [19:36:48] Starting 'styles'...
    [Browsersync] 4 files changed (main.css.map, main.css, media.css.map, media.css)
    [19:36:48] Finished 'styles' after 207 ms
    [19:36:48] Starting 'styles'...

这个循环是无止境的，直到我关闭终端

所以现在真正的问题更多是如何对属性进行排序，然后是如何避免循环。但我会对任何解决方案感到满意（避免循环，或另一种对属性进行排序的方式：vscode 的扩展，gulp 的插件等）

标签： node.jsnpmsassgulp

node.js - 如果此任务在此文件更改时启动，如何运行任务（更改文件）并避免循环

问题描述

解决方案

推荐阅读