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python - 如何读取 plist 中的响应字符串？

问题描述

我正在尝试解析 plist 以获取“此提交中修复了哪些更改错误？”字段的响应字符串，如下所示，但不知何故它总是为空？有人可以就错误的原因提供指导吗？

plist 片段：

<dict>
        <key>description</key>
        <string>What Change bugs are fixed in this submission? </string>
        <key>id</key>
        <string>7</string>
        <key>multiline</key>
        <string>1</string>
        <key>releases</key>
        <array>
            <string>Yukon</string>
        </array>
        <key>response</key>
        <string>&lt;change://problem/45317899&gt; hostapd to include IOKit framework
&lt;change://problem/35143400&gt; Yukon: hostapd-33 contains references to deprecated TARGET_OS_EMBEDDED macro</string>
    </dict>

代码：-

from lxml import etree as et
plistfile = '/Users/username/autosubmissionlogs/Yukon/02192019_200740/hostapd-34/hostapd-34.plist'
with open(plistfile) as raw:
    # Parse the XML input file into a tree.
    tree = et.parse(raw)
    stringUsedAsKey = tree.xpath("/plist/dict/dict/string"
            + "[./text()=\"What Change bugs are fixed in this submission?\"]")[0]
    interestingDict1 = stringUsedAsKey.getparent()
    string = interestingDict1.xpath("key[text()=\"response\"]/following-sibling::string")[0]
    print('Changes \n:'%string)

预期输出：-

&lt;change://problem/45317899&gt; hostapd to include IOKit framework
&lt;change://problem/35143400&gt; Yukon: hostapd-33 contains references to deprecated TARGET_OS_EMBEDDED macro

标签： pythonxmllxmlplistelementtree

解决方案

问题是您打印结果的方式。这是正确的方法。

from lxml import etree as et
plistfile = '/Users/username/autosubmissionlogs/Yukon/02192019_200740/hostapd-34/hostapd-34.plist'
with open(plistfile) as raw:
    # Parse the XML input file into a tree.
    tree = et.parse(raw)
    stringUsedAsKey = tree.xpath("/plist/dict/dict/string"
            + "[./text()=\"What Change bugs are fixed in this submission?\"]")[0]
    interestingDict1 = stringUsedAsKey.getparent()
    string = interestingDict1.xpath("key[text()=\"response\"]/following-sibling::string")[0]
    print("{}{}".format('Changes \n:', string.xpath("text()")))

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