首页 > 解决方案 > API 给出 ​​TypeError: unhashable type: 'dict'

问题描述

我正在开发一个 django-rest-framework API,我在其中对 VectorWise 数据库进行一些 SQL 查询和计算,并通过获取某些输入参数来创建响应。

起初,我的回复有这样的结构:

    response = {'Date': input_date,
                'Date comparable': date_comparable,
                'CA': {
                    'CA TTC (€)': ca_ttc_n,
                    'Rang magasin': rank,
                    'progression (%)': progression_percentage
                },
                'Nb art / pass caisse': {
                    'nombre': nb_art_pass_caiss,
                    'progression (%)': nb_art_pass_caiss_prog
                },
                'Panier': {
                    '(€)': panier,
                    'progression (%)': prog_panier}
                }

哪个工人很好,给我回复。

然后,我尝试改进响应的代码结构和可读性,如下所示:

    response = {'Date': input_date,
                'Comparable date': date_comparable,
                'Indicators': {
                    {"Name": "sales",
                     "Value": ca_ttc_n,
                     "Unit": currency,
                     "Rank": rank},
                    {"Name": "sales_progression",
                     "Value": progression_percentage,
                     "Unit": percentage,
                     "Rank": rank},
                    {"Name": "customer_items_number",
                     "Value": nb_art_pass_caiss,
                     "Unit": "Units",
                     "Rank": rank},
                    {"Name": "customer_items_number_progression",
                     "Value": nb_art_pass_caiss_prog,
                     "Unit": percentage,
                     "Rank": rank},
                    {"Name": "basket",
                     "Value": panier,
                     "Unit": currency,
                     "Rank": rank}
                }

另一方面,这会不断抛出 TypeError 的错误

Traceback (most recent call last):
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\core\handlers\exception.py", line 34, in inner
    response = get_response(request)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\core\handlers\base.py", line 115, in _get_response
    response = self.process_exception_by_middleware(e, request)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\core\handlers\base.py", line 113, in _get_response
    response = wrapped_callback(request, *callback_args, **callback_kwargs)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\views\decorators\csrf.py", line 54, in wrapped_view
    return view_func(*args, **kwargs)
  File "C:\ProgramData\Anaconda3\lib\site-packages\django\views\generic\base.py", line 71, in view
    return self.dispatch(request, *args, **kwargs)
  File "C:\ProgramData\Anaconda3\lib\site-packages\rest_framework\views.py", line 495, in dispatch
    response = self.handle_exception(exc)
  File "C:\ProgramData\Anaconda3\lib\site-packages\rest_framework\views.py", line 455, in handle_exception
    self.raise_uncaught_exception(exc)
  File "C:\ProgramData\Anaconda3\lib\site-packages\rest_framework\views.py", line 466, in raise_uncaught_exception
    raise exc
  File "C:\ProgramData\Anaconda3\lib\site-packages\rest_framework\views.py", line 492, in dispatch
    response = handler(request, *args, **kwargs)
  File "C:\ProgramData\Anaconda3\lib\site-packages\rest_framework_extensions\cache\decorators.py", line 49, in inner
    kwargs=kwargs,
  File "C:\ProgramData\Anaconda3\lib\site-packages\rest_framework_extensions\cache\decorators.py", line 68, in process_cache_response
    response = view_method(view_instance, request, *args, **kwargs)
  File "C:\Users\10124077\Projects\dataplatform--web--api\wdc\views.py", line 484, in get
    "Rank": rank}
TypeError: unhashable type: 'dict'

我尝试删除 rank 字段并进行一些操作以更好地理解该问题,但我没有设法做到这一点,因为它不断在响应正文的其他字段上引发 TypeError !有什么帮助吗?

标签: pythontypeerror

解决方案


问题在于:

'Indicators': {
                {"Name": "sales",
                 "Value": ca_ttc_n,
                 "Unit": currency,
                 "Rank": rank},
                {"Name": "sales_progression",
                 "Value": progression_percentage,
                 "Unit": percentage,
                 "Rank": rank},
                {"Name": "customer_items_number",
                 "Value": nb_art_pass_caiss,
                 "Unit": "Units",
                 "Rank": rank},
                {"Name": "customer_items_number_progression",
                 "Value": nb_art_pass_caiss_prog,
                 "Unit": percentage,
                 "Rank": rank},
                {"Name": "basket",
                 "Value": panier,
                 "Unit": currency,
                 "Rank": rank}
            }

...尝试创建一字典。所以,你的代码基本上是这样做的:

{{"this": "is", "a": "dictionary"}, {"within": "a set"}}

这是无法做到的,因为只能构造一组可散列对象,而dicts 不可散列。您可以在 docs 中了解“可散列”的含义。但是,您可以使用字典列表:

"Indicators": [
    {'Name': ..., 'Value': ...},
    {'Name': ..., 'Value': ...},
    ...
]

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