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首页 > 解决方案 > 我的 phpunit 的 assertEquals 说我的字符串不相等，但我已经复制了它们，我认为这是由于在响应中添加了行

php - 我的 phpunit 的 assertEquals 说我的字符串不相等，但我已经复制了它们，我认为这是由于在响应中添加了行

问题描述

我正在尝试使用 guzzle 运行一些测试来提示我的服务器提供 JSON 响应，我将与我期望的响应进行比较。问题是我无法得到与预期结果相匹配的响应。我认为这主要是由于一些语法错误，但我不知道如何纠正这个问题。

我已经尝试手动添加新行到输出应该是什么，但这只是将 \n 添加到字符串中。

请参阅下面的控制台报告：

1) UserAgentTest::testGet
Failed asserting that two strings are equal.
--- Expected
+++ Actual
@@ @@
-'{"error":false,"user":{"id_customer":10,"name":"Nic","email":"nparmee@gmail.com","password":"$2y$15$YN5A58syg5iIuHJ.5BR6j.ZpHGASqZID4l6k.M3xgH9jSPlojhzGK","x_coord":"-29.82188!-29.79044","y_coord":"31.02221!30.80688","address_name":"Home!Not home","address":"11 Rapson Road!11 everton road","country":null,"province":"KwaZulu-Natal!KwaZulu-Natal","city":"Durban!Durban","suburb":"Morningside!Kloof","postcode":"2639!3620","account":"sole","vat_num":"","reg_id":"","phone_number":"0836661065"}}'
+'
+
+{"error":false,"user":{"id_customer":10,"name":"Nic","email":"nparmee@gmail.com","password":"$2y$15$YN5A58syg5iIuHJ.5BR6j.ZpHGASqZID4l6k.M3xgH9jSPlojhzGK","x_coord":"-29.82188!-29.79044","y_coord":"31.02221!30.80688","address_name":"Home!Not home","address":"11 Rapson Road!11 everton road","country":null,"province":"KwaZulu-Natal!KwaZulu-Natal","city":"Durban!Durban","suburb":"Morningside!Kloof","postcode":"2639!3620","account":"sole","vat_num":"","reg_id":"","phone_number":"0836661065"}}'

C:\wamp64\www\tests\UserAgentTest.php:32

FAILURES!
Tests: 2, Assertions: 3, Failures: 1.

标签： phpphpunitguzzle

解决方案

“实际”字符串中有 2 个前导换行符：

+'
+
+{"error":false

trim您可以使用 PHP 的函数从字符串的开头和结尾去除空格。

 self::assertEquals(trim($string1), trim($string2));

这将确保没有前导/尾随空白字符。

此外，您可能希望删除所有换行符preg_replace：

self::assertEquals(
    trim(preg_replace('/\R+/', '', $string1)),
    trim(preg_replace('/\R+/', '', $string2))
);

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