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javascript - 如何从字符串中提取单个电子邮件地址？

问题描述

我需要从这种字符串中提取一个电子邮件地址。

未经授权：您的密码已过期。我们已向 example@gmail.com 发送了重置密码链接。请检查您的电子邮件以获取详细信息

const string = "Unauthorized: Your password has expired. We have sent a reset password link to example@gmail.com. Please check your email for details";
const mailMatch = string.match(/(\S+@[^\s.]+\.{1}[^.]\S+)/);

这种情况下的匹配将是这个`

[0: "example@gmail.com."
1: "example@gmail.com."
groups: undefined
index: 79
input: "Unauthorized: Your password has expired. We have sent a reset password link to example@gmail.com. Please check your email for details"
length: 2]

我不想匹配邮件末尾的点（表示句子的结尾）。如何更改我的正则表达式，以便仅获取example@gmail.com

标签： javascriptregex

解决方案

您可以使用

var string = "Unauthorized: Your password has expired. We have sent a reset password link to example@gmail.com. Please check your email for details";
var mailMatch = string.match(/\S+@[^\s.]+\.[^.\s]+/);
console.log(mailMatch); // => Matched text: example@gmail.com
// Or, if you may have any non-whitespace chars and you want to stop at the last
console.log(
  "The example@site.co.uk address is not available".match(/\S+@[^\s.]+\.\S+\b/)
); // => Matched text: example@site.co.uk
// Or just
console.log(
  "The example@some.site.co.uk address is not available".match(/\S+@\S+\.\S+\b/)
); // => Matched text: example@some.site.co.uk

由于尚不清楚您有一个更通用的示例是什么电子邮件要求

s.match(/\S+@\S+\.\S+\b/)

细节

  • \S+- 1+ 非空白字符
  • @- 一个@字符
  • \S+- 1+ 非空白字符
  • \.- 一个点
  • \S+\b- 1+ 个以单词边界结尾的非空白字符。

如果您只需要提取看起来有效的电子邮件，这里有一个对著名的电子邮件验证正则表达式稍作修改的解决方案：

var email_rx_extract = /(?:[^<>()[\]\\.,;:\s@"]+(?:\.[^<>()[\]\\.,;:\s@"]+)*|".+")@(?:\[\d{1,3}(?:\.\d{1,3}){3}]|(?:[a-zA-Z0-9-]+\.)+[a-zA-Z]{2,})(?![a-zA-Z])/g;
var s = "The example@some.site.co.uk address is not available\nBad email is example@gmail...........com.";
var results = s.match(email_rx_extract);
console.log(results); // => Only example@some.site.co.uk is found.

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