javascript - 循环遍历对象和数组的对象
问题描述
我有以下具有嵌套对象和数组的对象:
{
"children":[
{
"id":"9737ea0a-fa6f-42e1-bf16-a10af80e4d50",
"isCriteria":false,
"name":"Domain 1",
"children":[
{
"id":"e06d1940-b480-48e2-8e1a-2fe2a3910dfd",
"children":[
{
"id":"30995e1e-7195-4d01-85bf-c621398796cc",
"children":[
{
"id":"2969e48d-615e-4774-b92e-cbce768503ff",
"children":[
],
"isCriteria":true,
"name":"Criteria 1",
"questionType":"Yes/NO",
"importance":3
}
],
"isCriteria":false,
"name":"sub domain 1 - 2"
}
],
"isCriteria":false,
"name":"Sub domain 1"
},
{
"id":"c5b36f02-e765-4d93-970c-6faca94c28c1",
"children":[
{
"id":"6807ea4f-fb14-4d68-98f4-b3bf4c601e5c",
"children":[
],
"isCriteria":true,
"name":"Criteria 2",
"questionType":"5",
"importance":"1"
}
],
"isCriteria":false,
"name":"sub domain 2"
}
]
}
]
}
我想循环遍历它,直到我到达尾巴。并用其他数据编辑那个尾巴,因为.. in不会工作,因为我有数组
解决方案
您可以轻松地递归地执行此操作。
function recurse(node, level=0) {
if (node == null) return; // Check for null, exit
console.log(node.id == null ? 'root' : node.id); // Print the ID
if (node.children) node.children.forEach(child => recurse(child, level + 1)); // Hand off to children
}
下面代码的示例输出。
root
↓ ID: 9737ea0a-fa6f-42e1-bf16-a10af80e4d50
↳ Name: Domain 1
↓ ID: e06d1940-b480-48e2-8e1a-2fe2a3910dfd
↳ Name: Sub domain 1
↓ ID: 30995e1e-7195-4d01-85bf-c621398796cc
↳ Name: sub domain 1 - 2
↳ ID: 2969e48d-615e-4774-b92e-cbce768503ff
↳ Name: Criteria 1
↳ Type: Yes/NO
↳ Importance: 3
↓ ID: c5b36f02-e765-4d93-970c-6faca94c28c1
↳ Name: sub domain 2
↳ ID: 6807ea4f-fb14-4d68-98f4-b3bf4c601e5c
↳ Name: Criteria 2
↳ Type: 5
↳ Importance: 1
const data = loadData();
recurse(data);
function recurse(node, level=0) {
if (node == null) return;
let symbol = node.isCriteria ? '↳' : '↓';
let paddingOuter = ''.padStart((level - 1) * 2, ' ');
let paddingInner = ''.padStart((level + 1) * 2, ' ');
console.log(node.id == null ? 'root' : paddingOuter + symbol + ' ID: ' + node.id);
if (node.name) console.log(paddingInner + '↳ Name: ' + node.name);
if (node.isCriteria) {
console.log(paddingInner + '↳ Type: ' + node.questionType);
console.log(paddingInner + '↳ Importance: ' + node.importance);
}
if (node.children) node.children.forEach(child => recurse(child, level + 1));
}
function loadData() {
return {
"children": [{
"id": "9737ea0a-fa6f-42e1-bf16-a10af80e4d50",
"isCriteria": false,
"name": "Domain 1",
"children": [{
"id": "e06d1940-b480-48e2-8e1a-2fe2a3910dfd",
"children": [{
"id": "30995e1e-7195-4d01-85bf-c621398796cc",
"children": [{
"id": "2969e48d-615e-4774-b92e-cbce768503ff",
"children": [
],
"isCriteria": true,
"name": "Criteria 1",
"questionType": "Yes/NO",
"importance": 3
}],
"isCriteria": false,
"name": "sub domain 1 - 2"
}],
"isCriteria": false,
"name": "Sub domain 1"
},
{
"id": "c5b36f02-e765-4d93-970c-6faca94c28c1",
"children": [{
"id": "6807ea4f-fb14-4d68-98f4-b3bf4c601e5c",
"children": [
],
"isCriteria": true,
"name": "Criteria 2",
"questionType": "5",
"importance": "1"
}],
"isCriteria": false,
"name": "sub domain 2"
}
]
}]
};
}
.as-console-wrapper { top: 0; max-height: 100% !important; }
编辑数据
如果你需要编辑一个特定的节点,你可以通过它的 ID 来定位它并给它分配一个“新”的对象。它将覆盖现有属性并添加新属性。
function editNode(node, id, payload={}, found=false) {
if (node == null || id == null || found === true) return;
if (node.id === id) {
Object.assign(node, payload);
found = true;
}
if (found === false && node.children) {
node.children.forEach(child => editNode(child, id, payload, found));
}
}
↳ ID: 6807ea4f-fb14-4d68-98f4-b3bf4c601e5c
↳ Name: Criteria 2
↳ Question Type: 99 <-- MODIFIED BELOW
↳ Importance: 1
const data = loadData();
editNode(data, '6807ea4f-fb14-4d68-98f4-b3bf4c601e5c', { questionType : 99 })
recurse(data);
function recurse(node, level=0) {
if (node == null) return;
let symbol = node.isCriteria ? '↳' : '↓';
let paddingOuter = ''.padStart((level - 1) * 2, ' ');
let paddingInner = ''.padStart((level + 1) * 2, ' ');
console.log(node.id == null ? 'root' : paddingOuter + symbol + ' ID: ' + node.id);
if (node.name) console.log(paddingInner + '↳ Name: ' + node.name);
if (node.isCriteria) {
console.log(paddingInner + '↳ Question Type: ' + node.questionType);
console.log(paddingInner + '↳ Importance: ' + node.importance);
}
if (node.children) node.children.forEach(child => recurse(child, level + 1));
}
function editNode(node, id, payload={}, found=false) {
if (node == null || id == null || found === true) return;
if (node.id === id) {
Object.assign(node, payload);
found = true;
}
if (found === false && node.children) {
node.children.forEach(child => editNode(child, id, payload, found));
}
}
function loadData() {
return {
"children": [{
"id": "9737ea0a-fa6f-42e1-bf16-a10af80e4d50",
"isCriteria": false,
"name": "Domain 1",
"children": [{
"id": "e06d1940-b480-48e2-8e1a-2fe2a3910dfd",
"children": [{
"id": "30995e1e-7195-4d01-85bf-c621398796cc",
"children": [{
"id": "2969e48d-615e-4774-b92e-cbce768503ff",
"children": [
],
"isCriteria": true,
"name": "Criteria 1",
"questionType": "Yes/NO",
"importance": 3
}],
"isCriteria": false,
"name": "sub domain 1 - 2"
}],
"isCriteria": false,
"name": "Sub domain 1"
},
{
"id": "c5b36f02-e765-4d93-970c-6faca94c28c1",
"children": [{
"id": "6807ea4f-fb14-4d68-98f4-b3bf4c601e5c",
"children": [
],
"isCriteria": true,
"name": "Criteria 2",
"questionType": "5",
"importance": "1"
}],
"isCriteria": false,
"name": "sub domain 2"
}
]
}]
};
}
.as-console-wrapper { top: 0; max-height: 100% !important; }
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