首页 > 解决方案 > 如何在 for 循环中只添加一次列表?

问题描述

该代码正在运行并添加到列表中。但是,它向每个列表添加了三次而不是一次。我想将列表中的项目附加一次而不是三次。

我试图检查范围,它只是一个。但是,它仍然使用 append 方法添加到列表 3 次

newlist= [['id', 'name', 'lastContactedTime', 'email', 'phone_phones', 'home_phones', 'mobile_phones', 'work_phones', 'fax_phones', 'other_phones', 'address_1', 'address_2', 'address_3', 'city', 'state', 'postal_code', 'country', 'tags'], ['12-contacts', 'Courtney James', '', 'courtney@forlanchema.com', '+1 3455463849', '', '', '', '', '', '654 Rodney Franklin street', '', '', 'Birmingham', 'AL', '45678', 'US', ''], ['4-contacts', 'Joe Malcoun', '2019-08-13 14:41:12', 'ceo@nutshell.com', '', '', '', '', '', '', '212 South Fifth Ave', '', '', 'Ann Arbor', 'MI', '48103', 'US', ''], ['8-contacts', 'Rafael Acosta', '', 'racosta@forlanchema.com', '+1 338551534', '', '', '', '', '', '13 Jordan Avenue SW', '', '', 'Birmingham', 'AL', '45302', 'US', '']]
namelist = [] # new, empty list
for i in range(1, len(newlist)):
    names = newlist[i][1].split() # this yields [first_name, last_name]
    namelist.append([names[1], names[0]]) # [last_name, first_name]
companylist=[]
for i in range(1, len(newlist)):
    p = re.compile(r'(.+)@(.+)\.(.+)')
    test_str = newlist[i][3]
    company= re.findall(p, test_str)
    companyname= list(company[0][1])
    companynom=''.join(companyname)
    companylist.append(companynom) #yields company names
    # strip non-numeric characters'
    workphone = []
    wrkstreetaddress = []
    workcityaddress = []
    wrkstate = []
    wrkzip = []

for i in range(1, len(newlist)):
     phone = re.sub(r'\D', '', newlist[i][4])
 # remove leading 1 (area codes never start with 1)
     phone = phone.lstrip('1')
     workingphone= '{}.{}.{}'.format(phone[0:3], phone[3:6], phone[6:])
     workphone.append(workingphone) #yields a list of workphone numbers
     wrkstraddress= newlist[i][10]
     wrkstreetaddress.append(wrkstraddress) #yields a list of work street addresses
     wrkcityaddress= newlist[i][13] #yields a list of city addresses
     workcityaddress.append(wrkcityaddress)
     workstate= newlist[i][14] #yields a list of states
     wrkstate.append(workstate)
     workzip=newlist[i][15]
     wrkzip.append(workzip) #yields a list of zip codes

我希望每个列表都包含一个包含三个项目的列表:

如果我打印workstreetaddress list,我会得到:

print(wrskstreetaddress)

['654 Rodney Franklin street', '212 South Fifth Ave', '13 Jordan Avenue SW']
instead of:
['654 Rodney Franklin street']
['654 Rodney Franklin street', '212 South Fifth Ave']
['654 Rodney Franklin street', '212 South Fifth Ave', '13 Jordan Avenue SW']

从 companylist 到 wrkzip 的所有其他列表都相同我将项目添加三次而不是一次得到相同的结果

标签: pythonpython-3.xlistspyder

解决方案


一切都更好pandas

import pandas as pd

df = pd.DataFrame(newlist[1:], columns=newlist[0])

在此处输入图像描述

轻松将各个列提取到列表中,无需for-loops

addresses = df.address_1.tolist()

print(addresses)

['654 Rodney Franklin street', '212 South Fifth Ave', '13 Jordan Avenue SW']

轻松添加或重命名df列:

# split name into first and last name
df[['first_name', 'last_name']] = df.name.str.split(' ', expand=True)

# rename id
df.rename(columns={'id': 'id'}, inplace=True)

# split country_code from phone_phones
df[['country_code', 'phone_phones']] = df.phone_phones.str.split(' ', expand=True)

在此处输入图像描述

现在数据将更容易处理。


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