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php - 如何将一个字符串与另一个字符串值完全匹配？

问题描述

我有一个如下字符串的表值：

标签： phpmysqlsql

解决方案

一种方法是将传入的字符串拆分为单独的地址，然后检查它们是否都与表值匹配：

$string = 'PhysicalAddress:E8-6A-64-DE-48-60PhysicalAddress:04-EA-56-08-E6-8EPhysicalAddress:04-EA-56-08-E6-8FPhysicalAddress:06-EA-56-08-E6-8EPhysicalAddress:04-EA-56-08-E6-92';
$components = str_split($string, 33);
$query = "SELECT * 
FROM table1 
WHERE preview LIKE '%" . implode("%'\n  AND preview LIKE '%", $components) . "%'";
echo $query;

输出：

SELECT * 
FROM table1 
WHERE preview LIKE '%PhysicalAddress:E8-6A-64-DE-48-60%' 
  AND preview LIKE '%PhysicalAddress:04-EA-56-08-E6-8E%'
  AND preview LIKE '%PhysicalAddress:04-EA-56-08-E6-8F%'
  AND preview LIKE '%PhysicalAddress:06-EA-56-08-E6-8E%'
  AND preview LIKE '%PhysicalAddress:04-EA-56-08-E6-92%'

3v4l.org 上的演示

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