java - 无法使用 jackson 将 xml 绑定到 pojo,com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException:无法识别的字段
问题描述
当我尝试使用 jackson 将 xml 响应绑定到 POJO 时,我希望使用 getter 获取值。但我得到错误一个错误。我尝试搜索此内容,但找不到相关信息。大多数人建议使用忽略。但是我不能因为我期待那个领域。我的 pojo 如下所示。
public class Consumer {
private String xmlns;
private String version;
private Info info;
private Status status;
public Status getStatus() {
return status;
}
public void setStatus(Status status) {
this.status = status;
}
public Info getInfo() {
return info;
}
public void setInfo(Info info) {
this.info = info;
}
public String getXmlns() {
return xmlns;
}
public void setXmlns(String xmlns) {
this.xmlns = xmlns;
}
public String getVersion() {
return version;
}
public class Info {
private String state;
private String id;
private String shopId;
private String time;
public String getState() {
return state;
}
public void setState(String state) {
this.state = state;
}
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getShopId() {
return shopId;
}
public void setShopId(String shopId) {
this.shopId = shopId;
}
public String getTime() {
return time;
}
public void setTime(String time) {
this.time = time;
}
public class Status {
private Response response;
public Response getResponse() {
return response;
}
public void setResponse(Response response) {
this.response = response;
}
public class Response {
private String value;
private int statusCode;
private String messageCode;
public String getValue() {
return value;
}
public void setValue(String value) {
this.value = value;
}
public int getStatusCode() {
return statusCode;
}
public void setStatusCode(int statusCode) {
this.statusCode = statusCode;
}
public String getMessageCode() {
return messageCode;
}
public void setMessageCode(String messageCode) {
this.messageCode = messageCode;
}
public class Temp {
public static void main(String[] args) throws ParserConfigurationException, SAXException, IOException, JAXBException {
readXml();
}
public static void readXml() throws IOException, SAXException, ParserConfigurationException, JAXBException {
String xmlString = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n" +
"<Consumer xmlns=\"http://www.someurl.com\" version=\"1.5\">\n" +
" <Info state=\"CA\">\n" +
" <Id>160c464da1ad89a2fec50436</Id>\n" +
" <ShopId>1234</ShopId>\n" +
" <time>2019-08-22T23:13:47.909-04:00</time>\n" +
" </Info>\n" +
" <Status>\n" +
" <Response value=\"Success\" statusCode=\"3456\" messageCode=\"Request processed successfully\" />\n" +
" </Status>\n" +
"</Consumer>";
XmlMapper xmlMapper = new XmlMapper();
Consumer consumer = xmlMapper.readValue(xmlString, Consumer.class);
System.out.println("Shop id "+consumer.getInfo().getShopId());
}
Exception in thread "main" com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "Info" (class com.motivatedmind.api.stackoverflow.Consumer), not marked as ignorable (3 known properties: "version", "xmlns", "info"])
at [Source: (StringReader); line: `enter code here`3, column: 21] (through reference chain: com.motivatedmind.api.stackoverflow.Consumer["Info"])
at com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:61)
at com.fasterxml.jackson.databind.DeserializationContext.handleUnknownProperty(DeserializationContext.java:823)
at com.fasterxml.jackson.databind.deser.std.StdDeserializer.handleUnknownProperty(StdDeserializer.java:1153)
at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownProperty(BeanDeserializerBase.java:1589)
at com.fasterxml.jackson.databind.deser.BeanDeserializerBase.handleUnknownVanilla(BeanDeserializerBase.java:1567)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.vanillaDeserialize(BeanDeserializer.java:294)
at com.fasterxml.jackson.databind.deser.BeanDeserializer.deserialize(BeanDeserializer.java:151)
at com.fasterxml.jackson.databind.ObjectMapper._readMapAndClose(ObjectMapper.java:4014)
at com.fasterxml.jackson.databind.ObjectMapper.readValue(ObjectMapper.java:3005)
解决方案
我怀疑问题出在 XML 字符串本身。
将 更改<Consumersumer>
为<Consumer>
,这应该可以。
----------------------- 更新后---------
为什么state
是作为属性传递给 XML 标记“信息”..?它应该与<Info>
您的 POJO 类的实例值相匹配Info.java
。
状态是 POJO 中的实例变量,但不是标签中的子<info>
标签。
String xmlString = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n" +
"<Consumer xmlns=\"http://www.someurl.com\" version=\"1.5\">\n" +
" <Info>\n" +
" <State>CA</State>\n" +
" <Id>160c464da1ad89a2fec50436</Id>\n" +
" <ShopId>1234</ShopId>\n" +
" <time>2019-08-22T23:13:47.909-04:00</time>\n" +
" </Info>\n" +
" <Status>\n" +
" <Response value=\"Success\" statusCode=\"3456\" messageCode=\"Request processed successfully\" />\n" +
" </Status>\n" +
"</Consumer>";
尝试这个..!!
----------------- 更新后的评论---------
当您从其他服务获取数据(xml 字符串)时。您可以更改模型对象以与 xml 数据匹配。
为此,您可以在 pojo@XmlAttribute
中的字段设置方法上使用注释。state
有关更多参考,您可以查看此答案
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