sql - ORACLE - Interval between dates line by line

Question

Good afternoon, tell me, please, how to break the interval between dates line by line. I have a table:

with data as (
SELECT 1 AS id, 232 AS status, to_date('21.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('25.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 1 AS id, 235 AS status, to_date('25.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('27.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 1 AS id, 233 AS status, to_date('27.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 2 AS id, 301 AS status, to_date('20.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('23.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 2 AS id, 264 AS status, to_date('23.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('26.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
UNION ALL
SELECT 2 AS id, 259 AS status, to_date('26.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual)

select * from data

I want to get the result:

with result_data as (
SELECT 1 AS id, 232 AS status, to_date('21.08.2019') AS dte FROM dual
UNION ALL
SELECT 1 AS id, 232 AS status, to_date('22.08.2019') AS dte FROM dual
UNION ALL
SELECT 1 AS id, 232 AS status, to_date('23.08.2019') AS dte FROM dual
UNION ALL
SELECT 1 AS id, 232 AS status, to_date('24.08.2019') AS dte FROM dual
UNION ALL
SELECT 1 AS id, 235 AS status, to_date('25.08.2019') AS dte FROM dual
UNION ALL
SELECT 1 AS id, 235 AS status, to_date('26.08.2019') AS dte FROM dual
UNION ALL
SELECT 1 AS id, 233 AS status, to_date('27.08.2019') AS dte FROM dual
UNION ALL
SELECT 1 AS id, 233 AS status, to_date('28.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 301 AS status, to_date('20.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 301 AS status, to_date('21.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 301 AS status, to_date('22.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 264 AS status, to_date('23.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 264 AS status, to_date('24.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 264 AS status, to_date('25.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 259 AS status, to_date('26.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 259 AS status, to_date('27.08.2019') AS dte FROM dual
UNION ALL
SELECT 2 AS id, 259 AS status, to_date('28.08.2019') AS dte FROM dual)

select * from result_data

I tried to do through this request, but nothing worked for me

SELECT trunc(t.start_dte) + level -1 dte FROM (select * from data 
where data.end_dte != to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss')) t
CONNECT BY level < trunc(t.end_dte) - trunc(t.start_dte) + 1

There are a lot of rows in the table, are there any thoughts on how to do this rationally?

标签： sqloracle

Answer 1

我已经在您的示例中评论了 2999 年结束的日期范围，以使结果更加清晰：

with
maxdays
as
(select max( end_dte-start_dte )+1 days from 
    (SELECT 1 AS id, 232 AS status, to_date('21.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('25.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     UNION ALL
     SELECT 1 AS id, 235 AS status, to_date('25.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('27.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     --UNION ALL
     --SELECT 1 AS id, 233 AS status, to_date('27.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     UNION ALL
     SELECT 2 AS id, 301 AS status, to_date('20.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('23.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     UNION ALL
     SELECT 2 AS id, 264 AS status, to_date('23.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('26.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     --UNION ALL
     --SELECT 2 AS id, 259 AS status, to_date('26.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
    ) 
),
data
as
(select level-1 l from maxdays connect by level <= days )
select id,status,start_dte+l
  from data, (SELECT 1 AS id, 232 AS status, to_date('21.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('25.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     UNION ALL
     SELECT 1 AS id, 235 AS status, to_date('25.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('27.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     --UNION ALL
     --SELECT 1 AS id, 233 AS status, to_date('27.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     UNION ALL
     SELECT 2 AS id, 301 AS status, to_date('20.08.2019 10:47:39','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('23.08.2019 0:19:37','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     UNION ALL
     SELECT 2 AS id, 264 AS status, to_date('23.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('26.08.2019 0:25:11','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
     --UNION ALL
     --SELECT 2 AS id, 259 AS status, to_date('26.08.2019 19:11:00','dd.mm.yyyy hh24:mi:ss') AS start_dte, to_date('31.12.2999 23:59:59','dd.mm.yyyy hh24:mi:ss') AS end_dte FROM dual
    )
 where l <= end_dte-start_dte
 order by 2,3,1;