首页 > 解决方案 > 在 JavaScript 中同时使用字符串替换和正则表达式时如何获取捕获组的长度?

问题描述

我试图通过用 javaScript 字符串替换函数将私有数据的某些部分替换为星号(*)来实现一个简单的数据屏蔽函数。

所以我所做的如下:

    function privateDataMask(data, options) {
      var str = JSON.stringify(data);
      var i = 0, len = options.length;
    
      for (i; i < len; i++) {
        var opt = options[i];
        var key = opt.key;
        var reg = opt.reg;
        var _reg = new RegExp('"' + key + '":"' + reg.source + '"', 'g'); //To get new reg which includes the key, like /"tel":"(\d{3})(\d*)(\d{4})"/g
    
        str = str.replace(_reg, '"' + key + '":"$1*$3"');
        //str = str.replace(_reg, '"' + key + '":"$1' + '*'.repeat($2.length) + '$3",');           //ReferenceError: $2 is not defined
        //str = str.replace(_reg, '"' + key + '":"$1' + '*'.repeat(RegExp.$2.length) + '$3",');   //https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/RegExp/n
      }
      return JSON.parse(str);
    }
    
    var data = [{
        name: "王梅",
        tel: "15812346584",
        id: "22040219820418866X"
      }, {
        name: "吴青峰",
        tel: "13921345678",
        id: "450328197006157868"
      },
      {
        name: "王张玉成",
        tel: "17734685988",
        id: "620100198109198020"
      }
    ];
    
    var options = [{
        key: 'name',
        reg: /([\u4e00-\u9fa5A-Za-z0-9\·\.]?)([\u4e00-\u9fa5A-Za-z0-9\·\.]+)([\u4e00-\u9fa5A-Za-z0-9\·\.]+)/
      },
      {
        key: 'tel',
        reg: /(\d{3})(\d*)(\d{4})/
      },
      {
        key: 'id',
        reg: /(\d{6})(\d*)(\d{5}(\d|X){1})/
      }
    ]
    
    var maskedData = privateDataMask(data, options);
    console.log(maskedData);       

它以某种方式按预期工作,但我仍然想做一些小的改进,例如可以转移,名称:“吴青峰”->名称:“吴*峰”,名称:“王张玉成”->名称:“王**成”,电话:“15812346584”->电话:“158****6584”等。

也就是说,在替换的部分添加多个星号(),星号()的数量应该等于String.replace()期间捕获的组的长度。

正如注释行所表明的那样,我尝试过'*'.repeat(RegExp.$2.length)之类的东西,难题是RegExp.$n只能在String.replace()函数完成后才能获得价值,这会导致错位.

因此,请问有什么方法可以在 String.replace() 函数期间同时获取捕获组的长度吗?

标签: javascriptregexregex-groupdata-masking

解决方案


您可以将函数作为第二个参数传递给.replace(),该函数将计算*要添加的数量。

_str = _str.replace(_reg, (text, start, middle, end) => `"${key}":"${start + '*'.repeat(middle.length) + end}"`);

演示:

    function privateDataMask(data, options) {
        var str = JSON.stringify(data);
        var i = 0;
        var len = options.length;
        var _str, _data;
        for (i; i < len; i++) {
          var opt = options[i];
          var key = opt.key;
          var reg = opt.reg;
          var _reg = new RegExp('"' + key + '":"' + reg.source + '"',
            'g'); //To get new reg which includes the key, like /"tel":"(\d{3})(\d*)(\d{4})"/g
          //console.log(_reg);
          if (!_str) {
            _str = str;
          }
          _str = _str.replace(_reg, (text, start, middle, end) => `"${key}":"${start + '*'.repeat(middle.length) + end}"`);
        }
        _data = JSON.parse(_str);
        return _data;
      }
      
      var data = [{
          name: "王梅",
          tel: "15812346584",
          id: "22040219820418866X"
        }, {
          name: "吴青峰",
          tel: "13921345678",
          id: "450328197006157868"
        },
        {
          name: "王张玉成",
          tel: "17734685988",
          id: "620100198109198020"
        }
      ];
      
      var options = [{
          key: 'name',
          reg: /([\u4e00-\u9fa5A-Za-z0-9\·\.]?)([\u4e00-\u9fa5A-Za-z0-9\·\.]+)([\u4e00-\u9fa5A-Za-z0-9\·\.]+)/
        },
        {
          key: 'tel',
          reg: /(\d{3})(\d*)(\d{4})/
        },
        {
          key: 'id',
          reg: /(\d{6})(\d*)(\d{5}(\d|X){1})/
        }
      ]
      
      var maskedData = privateDataMask(data, options);
      console.log(maskedData);


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