首页 > 解决方案 > 父实体的主键未在子实体中存储为外键

问题描述

我在 Spring Data Jpa 中使用 OneToMany 关系并使用 postMan 测试 api

@Entity
@Table(name = "book_category")
public class BookCategory {
ParentEntity
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "bookCat_id")
    private Long id;

    private String name;

    @OneToMany(cascade = CascadeType.ALL, mappedBy="bookCategory")
    private Set<Book> books;

    public BookCategory(String name, Set<Book> books) {
        this.name = name;
        this.books = books;
    }

// getter and setter

}

ChildEntity


    @Entity
    @Table(name = "book")
    public class Book {

        @Id
        @GeneratedValue(strategy = GenerationType.IDENTITY)
        @Column(name = "book_id")
        private Long bookId;

        private String name;

        @ManyToOne(cascade = CascadeType.PERSIST)
        @JoinColumn(name = "bookCat_id")
        BookCategory bookCategory;

        public Book() {

        }

    //getter  and Setter

    }

控制器类

@RestController
@RequestMapping(value = "/bookCategory")
public class BookController {

    @Autowired
    BookCategoryRepository bookCategoryRepository;

    @Autowired
    BookRepository bookRepository;

    @PostMapping("/addBookCategory")
    public BookCategory savePerson(@Valid @RequestBody BookCategory bookCategory){
        return bookCategoryRepository.save(bookCategory);
    }
}

从邮递员调用 Rest Api 并将 json 传递为

{

    "name":"Category 1",
    "books":[
          {"name" : "Hello Koding 1"},
          {"name":"Hello Koding 2"}
        ]
} 

以下查询是由休眠执行的查询也是正确的,而我正在调用休息点 Hibernate:插入 book_category (name) values (?) Hibernate: insert into book (book_cat_id, name) values (?, ?)

它没有插入 book_cat_id,在 book_cat_id 中它传递了 null 所以 null 正在存储

数据库中存储的数据 book_category 数据库中的父表

book(ChildTable) book(ChildTable) I want to get Child Table Like 我想要这样的表

标签: javaspringspring-bootspring-data-jpa

解决方案


问题是您没有在子对象中设置父对象。您应该在代码中的某处调用

public void setBookCategory(BookCategory bookCategory) { ... }

Book 实体的方法。

我建议通过在控制器中使用 DTO 并将它们映射到服务层中的实体来解决此问题,因为使用持久实体作为 http 请求的参数可能会导致严重的安全漏洞,如此所述。

编辑:或者,即使我不鼓励这种解决方案,也可以像这样修改 savePerson 方法

@PostMapping("/addBookCategory")
public BookCategory savePerson(@Valid @RequestBody BookCategory bookCategory){
    bookCategory.getBooks().forEach(book -> book.setBookCategory(bookCategory));
    return bookCategoryRepository.save(bookCategory);
}

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