javascript - 如何根据MongoDB中的日期范围过滤数据

Question

[{
    "_id": {
        "$oid": "5d7a76c94c3c8c05618cef58"
    },
    "title": "hello",
    "date": {
        "$date": "2019-06-07T07:22:00.000Z"
    },
    "__v": 0
}, {
    "_id": {
        "$oid": "5d7a7809ef31980615ed3756"
    },
    "title": "hello",
    "date": {
        "$date": "2019-06-08T07:22:00.000Z"
    },
    "__v": 0
}, {
    "_id": {
        "$oid": "5d7a78e712c75706a3fdb025"
    },
    "title": "hello6",
    "date": {
        "$date": "2019-07-19T08:22:00.000Z"
    },
    "__v": 0
}, {
    "_id": {
        "$oid": "5d7a78e712c75706a3fdb025"
    },
    "title": "hello7",
    "date": {
        "$date": "2019-07-03T08:22:00.000Z"
    },
    "__v": 0
}]

我正在使用 mongoose 将我的数据存储在 mongodb 中，我正在尝试使用过滤我的数据mongoose

2019-07-01我想要从日期到的所有文档。2019-07-31我们可以在 mongoDB 中对 mongoose 进行此过滤吗

预期产出

[
{
    "_id": {
        "$oid": "5d7a78e712c75706a3fdb025"
    },
    "title": "hello6",
    "date": {
        "$date": "2019-07-19T08:22:00.000Z"
    },
    "__v": 0
}, {
    "_id": {
        "$oid": "5d7a78e712c75706a3fdb025"
    },
    "title": "hello7",
    "date": {
        "$date": "2019-07-03T08:22:00.000Z"
    },
    "__v": 0
}
]

这是我的代码 https://codesandbox.io/s/lively-tree-hd0fo

app.get("/saveData", async () => {
  try {
    var blog = new BlogPostModel({
      title: "hello6",
      date: "19-Jul-2019 08:22"
    });
    console.log("before save");
    let saveBlog = await blog.save(); //when fail its goes to catch
    console.log(saveBlog); //when success it print.
    console.log("saveBlog save");
  } catch (error) {
    console.log(error);
  }
});

标签： javascriptnode.jsmongodbmongoose

Answer 1

您可以使用 MongoDB 的$gte（大于或等于）和$lte（小于或等于）：

blog.find({ date: { $gte: '2019-07-01', $lte: '2019-07-31' } });