typescript - 如何通过另一个类扩展类？

Question

我有树类：

class ClassificatorOrganizationsModel {
    protectedcode: string | undefined;
}

class EduUnitModel {
  paren1tId: number | undefined;
  paren2tId: number | undefined;
  paren3tId: number | undefined;
  phone: string | undefined;
}

export class EduOrganizationModel {
  regionId: number | undefined;
  addressId: number | undefined;

}

我需要该类EduOrganizationModel将由EduUnitModeland扩展ClassificatorOrganizationsModel。

结果，我需要获得EduOrganizationModel包括孩子在内的所有属性的课程。

所以，我不能这样做：

class EduOrganizationModel extends EduUnitModel, ClassificatorOrganizationsModel {
}

如何解决？

标签： typescripttypescript2.0

Answer 1

您可以使用 Mixins https://www.typescriptlang.org/docs/handbook/mixins.html 进行多重继承。

interface EduOrganizationModel extends EduUnitModel, ClassificatorOrganizationsModel {}
applyMixins(EduOrganizationModel, [EduUnitModel, ClassificatorOrganizationsModel]);

function applyMixins(derivedCtor: any, baseCtors: any[]) {
    baseCtors.forEach(baseCtor => {
        Object.getOwnPropertyNames(baseCtor.prototype).forEach(name => {
            Object.defineProperty(derivedCtor.prototype, name, Object.getOwnPropertyDescriptor(baseCtor.prototype, name));
        });
    });
}