javascript - JavaScript find highest version from array of dotted versions

Question

I have a array of version numbers looking like this:

[
  {
    "name": "v12.3.0.pre",
  },
  {
    "name": "v12.2.5",
  },
  {
    "name": "v12.2.4",
  },
  {
    "name": "v12.2.3",
  },
  {
    "name": "v12.2.1",
  },
  {
    "name": "v12.2.0",
  },
  {
    "name": "v12.2.0.pre",
  },
  {
    "name": "v12.2.0-rc32",
  },
  {
    "name": "v12.2.0-rc31",
  },
  {
    "name": "v12.1.9",
  },
  {
    "name": "v12.1.8",
  },
  {
    "name": "v12.1.6",
  },
  {
    "name": "v12.1.4",
  },
  {
    "name": "v12.1.3",
  },
  {
    "name": "v12.1.2",
  },
  {
    "name": "v12.1.1",
  },
  {
    "name": "v12.1.0",
  },
  {
    "name": "v12.1.0.pre",
  },
  {
    "name": "v12.1.0-rc23",
  },
  {
    "name": "v12.1.0-rc22",
  },
  {
    "name": "v12.0.9",
  },
  {
    "name": "v12.0.8",
  },
  {
    "name": "v12.0.6",
  },
  {
    "name": "v12.0.4",
  },
  {
    "name": "v12.0.3",
  },
  {
    "name": "v12.0.2",
  },
  {
    "name": "v12.0.1",
  },
  {
    "name": "v12.0.0",
  },
  {
    "name": "v11.12.0.pre",
  },
  {
    "name": "v11.11.8",
  }
]

From this array I would like to determine the latest version, which do not end with '.pre' or include 'rc.

I'm iterating through the array with a for-loop, and filtering out the '.pre' and 'rc' with an if statement. I then use split/join to remove the first 'v' character. So far so good. Then I'm left with values like '12.2.5' and '11.12.10'. I first thought of removing the dots, then use a 'greater than' operator to see find the highest value, but then '11.12.10(111210)' would result greater than '12.2.5(1225)' which would not work out in my case.

for(i in arr){
    if(!arr[i].name.endsWith('.pre') && !arr[i].name.includes('rc')){
        var number = number.split('v').join("");
        var number = number.split('.').join("");
    }
}

Any ideas on best way to solve this? Thanks!

标签： javascriptarrays

Answer 1

您可以String#localeCompare选择获得结果的选项。

var data = [{ name: "v12.3.0.pre" }, { name: "v12.2.5" }, { name: "v12.2.4" }, { name: "v12.2.3" }, { name: "v12.2.1" }, { name: "v12.2.0" }, { name: "v12.2.0.pre" }, { name: "v12.2.0-rc32" }, { name: "v12.2.0-rc31" }, { name: "v12.1.9" }, { name: "v12.1.8" }, { name: "v12.1.6" }, { name: "v12.1.4" }, { name: "v12.1.3" }, { name: "v12.1.2" }, { name: "v12.1.1" }, { name: "v12.1.0" }, { name: "v12.1.0.pre" }, { name: "v12.1.0-rc23" }, { name: "v12.1.0-rc22" }, { name: "v12.0.9" }, { name: "v12.0.8" }, { name: "v12.0.6" }, { name: "v12.0.4" }, { name: "v12.0.3" }, { name: "v12.0.2" }, { name: "v12.0.1" }, { name: "v12.0.0" }, { name: "v11.12.0.pre" }, { name: "v11.11.8" }],
    highest = data
        .filter(({ name }) => !name.endsWith('.pre') && !name.includes('rc'))
        .reduce((a, b) =>
            0 < a.name.localeCompare(b.name, undefined, { numeric: true, sensitivity: 'base' })
                ? a
                : b
        );

console.log(highest);

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