c++ - 在第二个监视器中显示图像的 C++ 列表屏幕

问题描述

我想在第二台显示器上显示图像。我在 Ubuntu 中有两个 1920x1080 像素的显示器连接并正确检测到。

我列出了带有以下代码的屏幕。问题是我总是只列出一个屏幕0：1920x1080 用于单显示器配置，3840x1080 用于多显示器（扩展或复制）。

如何获取两个显示器的列表以便仅选择 screen1（第二个显示器 1920x1080）？

Display *myDisplay = XOpenDisplay(NULL);

unsigned int numScreens = ScreenCount(myDisplay);

for(unsigned int i=0; i<numScreens; i++){

    Screen *myScreen = ScreenOfDisplay(myDisplay, i);
    ScreenInfo screen;
    screen.resX = myScreen->width;
    screen.resY = myScreen->height;
    char screenName[50];
    sprintf(screenName, "Screen number %d", i);
    screen.name = screenName;

}

更新：这是我的 xrandr 输出，显示两个显示器正确连接，我可以相应地使用它。但是，如果我访问可用的显示器，我只能得到：0 一个屏幕，3840x1080。如何获得两个显示（：0和：1）？

vo@vo-ubuntu:~$ xrandr
Screen 0: minimum 320 x 200, current 1920 x 1080, maximum 8192 x 8192
HDMI-1 connected 1920x1080+0+0 (normal left inverted right x axis y axis) 527mm x 296mm
   1920x1080     60.00*+  60.00    50.00    50.00    59.94  
   1920x1080i    60.00    60.00    50.00    59.94  
   1600x1200     60.00  
   1680x1050     59.88  
   1400x1050     59.95  
   1600x900      60.00  
   1280x1024     75.02    60.02  
   1440x900      59.90  
   1280x960      60.00  
   1152x864      75.00  
   1280x720      60.00    60.00    50.00    59.94  
   1024x768      75.03    70.07    60.00  
   832x624       74.55  
   800x600       72.19    75.00    60.32    56.25  
   720x576       50.00    50.00  
   720x576i      50.00    50.00  
   720x480       60.00    60.00    59.94    59.94    59.94  
   720x480i      60.00    60.00    59.94    59.94  
   640x480       75.00    72.81    66.67    60.00    59.94    59.94  
   720x400       70.08  
HDMI-2 disconnected (normal left inverted right x axis y axis)
DP-1 connected primary 1920x1080+0+0 (normal left inverted right x axis y axis) 527mm x 296mm
   1920x1080     60.00*+
   1600x1200     60.00  
   1680x1050     59.95  
   1400x1050     59.98  
   1600x900      60.00  
   1280x1024     75.02    60.02  
   1440x900      59.89  
   1280x960      60.00  
   1152x864      75.00  
   1280x720      60.00  
   1024x768      75.03    70.07    60.00  
   832x624       74.55  
   800x600       72.19    75.00    60.32    56.25  
   640x480       75.00    72.81    66.67    59.94  
   720x400       70.08  
DVI-D-1-1 disconnected (normal left inverted right x axis y axis)
HDMI-1-3 disconnected (normal left inverted right x axis y axis)
DP-1-2 disconnected (normal left inverted right x axis y axis)

检查可用的 X 显示器不返回两个连接的显示器，

vo@vo-ubuntu:~$ cd /tmp/.X11-unix && for x in X*; do echo ":${x#X}"; done
:0
:1024
vo@vo-ubuntu:/tmp/.X11-unix$

标签： c++ubuntux11

c++ - 在第二个监视器中显示图像的 C++ 列表屏幕

问题描述

解决方案

推荐阅读