android - 阻塞时在Kotlin中调用String方法

Question

目前我有一个像这样的 when 块：

val foo = getStringFromBar()

when {
    foo == "SOMETHING" -> { /*do stuff*/ }
    foo == "SOMETHING ELSE" -> { /*do other stuff*/ }
    foo.contains("SUBSTRING") -> { /*do other other stuff*/ }
    else -> { /*do last resort stuff*/ }
}

有没有办法把它简化成这样：

val foo = getStringFromBar()

when (foo) {
    "SOMETHING" -> { /*do stuff*/ }
    "SOMETHING ELSE" -> { /*do other stuff*/ }
    .contains("SUBSTRING") -> { /*do other other stuff*/ }  // This does not work
    else -> { /*do last resort stuff*/ }
}

标签： androidkotlinsyntaxkotlin-when

Answer 1

您可以使用with

试试这个方法

    with(foo) {
        when {
            equals("SOMETHING") -> println("Case 1")
            equals("something",false) -> println("Case 2")
            contains("SUBSTRING") -> println("Case 3")
            contains("bar") -> println("Case 4")
            startsWith("foo") -> println("Case 5")
            else -> println("else Case")
        }
    }