python - 如果输入不符合 for 循环的要求，如何强制用户重新输入？

Question

这是我的代码，要求用户输入他们想要生成的密码字符数。如果他们输入数字 < 8，我想强制他们重新输入。否则，将生成密码。但我被 for 循环卡住了，因为它产生了无限期的打印。

任何帮助，将不胜感激。

import string
import random

lower_string = string.ascii_lowercase
upper_string = string.ascii_uppercase
special_string = "!@#$%&*()[]{}"
number = '0123456789'

list_string = [lower_string, upper_string, special_string, number]

password = ''

password_length = int(input("Enter length of password: "))


while password_length < 8:
    print("Hey, this password's length is not good. Enter > 8")
    continue
else:
    for _ in range(password_length):
        x = random.choice(random.choice(list_string)) 
        password = password + x
print(password)

标签： pythonpython-3.xwhile-loop

Answer 1

尝试将input语句放在 while 循环中

while True:
    password_length = int(input("Enter length of password: "))
    if password_length < 8:
        print("Hey, this password's length is not good. Enter > 8")
    else:
        break