首页 > 解决方案 > 在 Python 中编写多个条件是否有不同的方法?

问题描述

我是 python 新手,我正在做 TWO + TWO = FOUR,其中每个字母代表 1-10 的不同数字。我需要找到所有组合。我想知道是否有更好的写法,尤其是'if'和'for'

for t in range (1,10):
  for f in range (1,10):
    for w in range(10):
      for o in range(10):
        for u in range(10):
          for r in range(10):
            if 2*(t*100 + w*10 + o) == f*1000 + o*100 + u*10 + r and t is not f and t is not w and t is not o and t is not u and t is not r and f is not w and f is not o and f is not o and f is not u and f is not r and w is not o and w is not u and w is not r and o is not u and o is not r and u is not r:
              print(t,w,o, "and", f,o,u,r)

我试过这样写,但它给了我超过 7 个结果

if 2*(t*100 + w*10 + o) == f*1000 + o*100 + u*10 + r and t != f != w != o != u != r

标签: pythonpython-3.xcryptarithmetic-puzzle

解决方案


您可以使用这样的简单技巧:

for t in range (1,10):
  for f in range (1,10):
    for w in range(10):
      for o in range(10):
        for u in range(10):
          for r in range(10):
            if 2*(t*100 + w*10 + o) == f*1000 + o*100 + u*10 + r and len(set([t,f,w,o,u,r])) == 6:
              print(t,w,o, "and", f,o,u,r)

这个想法set只是存储不同的数字,所以如果它们是成对不同的,那么集合的长度应该等于变量的数量


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