时间戳

首页 > 解决方案 > 缩写词和连字符的打印

python - 缩写词和连字符的打印

问题描述

我需要识别句子中的所有缩写词和连字符才能开始。当它们被识别时，它们需要被打印出来。我的代码似乎不能很好地进行这种识别。

import re

sentence_stream2=df1['Open End Text']
for sent in sentence_stream2:
    abbs_ = re.findall(r'(?:[A-Z]\.)+', sent) #abbreviations
    hypns_= re.findall(r'\w+(?:-\w+)*', sent) #hyphenated words

    print("new sentence:")
    print(sent)
    print(abbs_)
    print(hypns_)

我的语料库中的一句话是：DevOps with APIs & event-driven architecture using cloud Data Analytics environment Self-service BI

输出是：

new sentence:
DevOps with APIs & event-driven architecture using cloud Data Analytics environment Self-service BI
[]
['DevOps', 'with', 'APIs', 'event-driven', 'architecture', 'using', 'cloud', 'Data', 'Analytics', 'environment', 'Self-service', 'BI']

预期输出是：

new sentence:
DevOps with APIs & event-driven architecture using cloud Data Analytics environment Self-service BI
['APIs','BI']
['event-driven','Self-service']

标签： pythontextabbreviationhyphenation

解决方案

您的缩写规则不匹配。你想找到任何超过 1 个连续大写字母的单词，你可以使用的规则是：

abbs_ = re.findall(r'(?:[A-Z]{2,}s?\.?)', sent) #abbreviations

这将匹配 API 和 BI。

t = "DevOps with APIs & event-driven architecture using cloud Data Analytics environment Self-service BI"

import re

abbs_ = re.findall(r'(?:[A-Z]\.)+', t) #abbreviations
cap_ = re.findall(r'(?:[A-Z]{2,}s?\.?)', t) #abbreviations
hypns_= re.findall(r'\w+-\w+', t) #hyphenated words fixed

print("new sentence:")
print(t)
print(abbs_)
print(cap_)
print(hypns_)

输出：

DevOps with APIs & event-driven architecture using cloud Data Analytics environment Self-service BI
[]  # your abbreviation rule - does not find any capital letter followed by .
['APIs', 'BI'] # cap_ rule
['event-driven', 'Self-service']  # fixed hyphen rule

这很可能找不到所有缩写，例如

t = "Prof. Dr. S. Quakernack"

所以您可能需要使用更多数据和 fe http://www.regex101.com对其进行调整

推荐阅读