c++ - c ++:if语句无法正常运行并进入无效输出
问题描述
刚开始学习 c++ 并尝试制作一个自动订购系统,但是在继续使用它之前尝试运行时我遇到了这个问题:
#include <iostream>
using namespace std;
char acoustic, fender, hartwood, electric, gibson, ibanez, drums, pearl,
roland, piano, casio;
char rolandpi, equip, string, headphone, amp, mixer, micro, tuner, pick,
music, Yes, No;
int pay1 = 0, pay2 = 0;
int main()
{
cout << "Welcome to the Music Shop" << endl <<endl;
cout << "a. Acoustic Guitar" << endl;
cout << "a.1 Fender Acoustic Guitar - P6,900.00" << endl;
cout << "a.2 Hartwood Acoustic Guitar - P6,300.00" << endl <<endl;
cout << "b. Electric Guitar" << endl;
cout << "b.1 Gibson Electric Guitar -P8,500.00" << endl;
cout << "b.2 Ibanez Electric Guitar -P25,000.00" << endl <<endl;
cout << "c. Drums" << endl;
cout << "c.1 Pearl Drum Kits -P27,000.00" << endl;
cout << "c.2 Roland Electronic Drums -P24,000.00" << endl <<endl;
cout << "d. Piano" << endl;
cout << "d.1 Casio Digital Piano -P19,000.00" << endl;
cout << "d.2 Roland Piano -P120,000.00" << endl <<endl;
cout << "e. Music Equipments" << endl;
cout << "e.1 Guitar String -P113.00" << endl;
cout << "e.2 Headphones -P1,600.00" << endl;
cout << "e.3 Amplifier -P2,800.00" << endl;
cout << "e.4 Digital Mixer -P4,750.00" << endl;
cout << "e.4 Vocal Microphone -P860.00" << endl;
cout << "e.5 Guitar Tuner -P537.00" << endl;
cout << "e.6 Guitar Pick -P360.00" << endl <<endl;
cout << "Choose the music instrument or equipment you want to buy: ";
cin >> music;
switch (music)
{
case 'a':
cout<< "Acoustic Guitar" << endl;
cout<< "1. Fender Acoustic Guitar - P6,900.00" << endl;
cout<< "2. Hartwood Acoustic Guitar - P6,300.00" << endl <<endl;
cout<<"Choose from the available Acoustic Guitars:";
cin>>acoustic;
if (acoustic == 1){
cout<<"Enter your payment:";
cin>>pay1;
if (pay1=6900){
cout<<"You have succesfully purchased Fender Acoustic Guitar"<<endl;
}
else if (pay1>6900){
pay1 -= 6900;
cout<<"Your change is:"<<pay1<<endl;
}
else (pay1<6900);
{
cout<<"You do not have enough money"<<endl;
}
}
else if (acoustic == 2){
cout<<"Enter your payment:";
cin>>pay1;
if (pay1=6300){
cout<<"You have succesfully purchased Fender Acoustic Guitar"<<endl;
}
else if (pay1>6300){
pay1 -= 6300;
cout<<"Your change is:"<<pay1<<endl;
}
else (pay1<6300);
{
cout<<"You do not have enough money"<<endl;
}
}
else {
cout<<"Invalid"<<endl;
}
}
}
我已经检查了我的if else
陈述,找不到什么问题。
输入1
或2
从“从可用的原声吉他中选择”后,它会继续“无效”。
解决方案
char
你在这里读到:
cout << "Choose from the available Acoustic Guitars:";
cin >> acoustic;
但是你int
稍后将它与一行进行比较:
if (acoustic == 1) {
相反,这应该是:
if (acoustic == '1') {
还有这个:
if (pay1 = 6900) {
应该:
if (pay1 == 6900) {
因为否则无论输入什么,您都会得到不正确的输出,因为pay1 = 6900
设置pay1
为6900
并返回6900
,它被隐式转换为true
.
还有这一行:
else (pay1 < 6900);
需要改为
else if (pay1 < 6900)
因为否则(pay1 < 6900)
不是if
语句的条件,而是在这种情况下(pay1 < 6900);
发生的情况(它只是计算一个布尔值并丢弃它),导致始终打印else
以下消息。"You do not have enough money"
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