时间戳

首页 > 解决方案 > 在函数中传递结构

c - 在函数中传递结构

问题描述

以下代码在编译时出错：

int add_employee(struct emp e)
     {
        printf("%i\n", e.emp_no);
        printf("Date of Birth:\n");
        printf("%i / %i / %i\n", e.birth_date.dd, e.birth_date.mm, e.birth_date.yyyy);
        printf("%s %s\n", e.first_name, e.last_name);
        printf("%s\n", e.gender);
        printf("Date of Hirting:\n");
        printf("%i / %i / %i\n", e.hire_date.dd, e.hire_date.mm, e.hire_date.yyyy);
        return 0;
    }

    int main()
    {
        struct employees emp, *ptr;
        ptr = &emp;
        int i=0;
        ptr->emp_no = get_int("Employee No.: ");
        printf("Date of Birth:\n");
        ptr->birth_date.dd = get_int("Date: ");
        ptr->birth_date.mm = get_int("Month: ");
        ptr->birth_date.yyyy = get_int("Year: ");
        ptr->first_name = get_string("First Name: ");
        ptr->last_name = get_string("Last Name: ");
        ptr->gender = get_string("Gender(M/F): ");
       printf("Date of Hiring:\n");
       ptr->hire_date.dd = get_int("Date: ");
       ptr->hire_date.mm = get_int("Month: ");
       ptr->hire_date.yyyy = get_int("Year: ");
      i = add_employee(emp);
       if(i == 0)
       {
           printf("Employee added successfully\n");
       }

以下是我使用 clang 编译时的错误：

app.c:75:25：警告：“struct emp”的声明在此函数之外不可见 [-Wvisibility]
int add_employee(struct emp e)
                        ^ 
app.c:75:29：错误：变量的类型不完整 'struct emp'
int add_employee(struct emp e)
                            ^ 
app.c:75:25:注意： 'struct emp' 的前向声明
int add_employee(struct emp e)
                        ^ 
app.c:104:22：错误：参数类型“struct emp”不完整
    i = add_employee(emp);
                     ^~~ 
app.c:75:25:注意: 'struct emp' 的前向声明
int add_employee(struct emp e)
                        ^
生成 1 个警告和 2 个错误。

标签： cfunctionstructure

解决方案

Looking at the line in main

struct employees emp, *ptr;

It seems the type is struct employees.

So function should be

int add_employee(struct employees e)

推荐阅读