java - Forcing Code to wait for condition using while loop requires thread.sleep()
问题描述
I've created a program that divides a linear search (searches for -1) up onto 4 separate threads.
public class main {
static boolean found = false;
public static void main(String[] args) {
// TODO Auto-generated method stub
int threadCount = 4; //amount of threads to use
Random rand = new Random();
Searcher[] s_arr = new Searcher[threadCount]; //array of threads
int[] arr = new int[10000]; //array to search through
for (int i = 0; i < arr.length; i++) //randomizing #'s in array
arr[i] = (int) (rand.nextFloat() * 1000);
int randIndex = rand.nextInt(arr.length); //choose random index
arr[randIndex] = -1; //set random index to = -1
for (int i = 0; i < threadCount; i++) { //
s_arr[i] = new Searcher(Arrays.copyOfRange(arr, i * (arr.length/threadCount), (i+1) * (arr.length/threadCount)),
(int) (i), i); //assign subarray for this thread to search through
System.out.println(s_arr[i].wait);
s_arr[i].start();
}
//CODE IN QUESTION HERE ----------------------------
//while (!found) ;
while (!found) //wait until value is found
{
try {
Thread.sleep(1);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
//-----------------------------------------------------------
System.out.println("found!");
for (int i = 0; i < threadCount; i++) {
try {
s_arr[i].join(); //wait for the threads in order before continuing
System.out.println("Thread ["+i+"] completed");
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
System.out.println("All threads stopped, program complete.");
}
}
public class Searcher extends Thread {
int[] arr;
int wait;
int index;
public Searcher(int[] arr, int wait, int i) {
this.arr = arr;
this.wait = wait;
this.index = i;
}
@Override
public void run() {
for (int i = 0; i < arr.length; i++) {
if (arr[i] == -1) {
System.out.println("["+index+"] -1 Found at index: "+i);
main.found = true;
break;
}
if (main.found) break;
//purposely slow down this thread
try {
Thread.sleep(wait);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
System.out.println("["+index+"] has stopped");
}
}
I've marked out the code in question, while using the first (commented out) while loop, the program doesn't move beyond that point, but if I switch and use the other while loop right below it (the one that forces it to wait 1 millisecond each iterator) the program works just fine.
Why is this and is there a more efficient/practical way to accomplish this task?
解决方案
在空循环语句的条件下重复读取非易失性字段可能会导致无限循环,因为编译器优化可能会将此字段访问移出循环。
资源:help.semmle.com
如果替换static boolean found = false;
为volatile static boolean found = false;
,第一个循环将起作用,但我不推荐它,因为它会浪费您的 CPU 时间。您应该考虑使用wait
and notify
。
下面static boolean found
,添加static final Object lock = new Object();
和替换两个while
循环
try {
synchronized (lock) {
// we will wait here until we get notified
lock.wait();
}
} catch (InterruptedException e) {
e.printStackTrace();
}
main.found = true
添加后也是
synchronized (main.lock) {
main.lock.notify();
}
最后,您的代码应如下所示
public class main {
static boolean found;
static final Object lock = new Object();
public static void main(String[] args) {
// TODO Auto-generated method stub
int threadCount = 4; //amount of threads to use
Random rand = new Random();
Searcher[] s_arr = new Searcher[threadCount]; //array of threads
int[] arr = new int[10000]; //array to search through
for (int i = 0; i < arr.length; i++) //randomizing #'s in array
arr[i] = (int) (rand.nextFloat() * 1000);
int randIndex = rand.nextInt(arr.length); //choose random index
arr[randIndex] = -1; //set random index to = -1
for (int i = 0; i < threadCount; i++) { //
s_arr[i] = new Searcher(Arrays.copyOfRange(arr, i * (arr.length/threadCount), (i+1) * (arr.length/threadCount)),
(int) (i), i); //assign subarray for this thread to search through
System.out.println(s_arr[i].wait);
s_arr[i].start();
}
try {
synchronized (lock) {
lock.wait();
}
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("found!");
for (int i = 0; i < threadCount; i++) {
try {
s_arr[i].join(); //wait for the threads in order before continuing
System.out.println("Thread ["+i+"] completed");
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
System.out.println("All threads stopped, program complete.");
}
}
class Searcher extends Thread {
int[] arr;
int wait;
int index;
public Searcher(int[] arr, int wait, int i) {
this.arr = arr;
this.wait = wait;
this.index = i;
}
@Override
public void run() {
for (int i = 0; i < arr.length; i++) {
if (arr[i] == -1) {
System.out.println("["+index+"] -1 Found at index: "+i);
main.found = true;
synchronized (main.lock) {
main.lock.notify();
}
break;
}
if (main.found) break;
//purposely slow down this thread
try {
Thread.sleep(wait);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
System.out.println("["+index+"] has stopped");
}
}
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