首页 > 解决方案 > 我想写代码来更新Java中的mysql数据。这是我的代码。它给出了这样的错误:

问题描述

 private void jButton2ActionPerformed(java.awt.event.ActionEvent evt) {                                         
    // TODO add your handling code here:
       DefaultTableModel d1 = (DefaultTableModel)jTable2.getModel();
        int selectIndex = jTable2.getSelectedRow();                     
        int id = Integer.parseInt(d1.getValueAt(selectIndex, 0).toString());

          String bname = txtname.getText();
    CategoryItem citem = (CategoryItem) txtcategory.getSelectedItem();
  AuthorItem aitem = (AuthorItem) txtauthor.getSelectedItem();
   PublisherItem pitem = (PublisherItem) txtpub.getSelectedItem(); 

   String contents = txtcontent.getText();
   String pages = txtno.getText();
   String edition = txtedition.getText();

    try {
        pst = con.prepareStatement("update book set bname= ? , category= ? , author= ? , publisher= ? , contents= ? , pages= ? , edition= ? , where id= ? ");
        pst.setString(1, bname);
        pst.setInt(2, citem.id);
        pst.setInt(3, aitem.id);
        pst.setInt(4, pitem.id);
        pst.setString(5, contents);
        pst.setString(6, pages);
        pst.setString(7, edition);
        pst.setInt(8,id);
        int k=pst.executeUpdate();

        if(k==1)
        {
            JOptionPane.showMessageDialog(this,"Book Added");       
            txtname.setText("");
            txtcategory.setSelectedIndex(-1);
            txtauthor.setSelectedIndex(-1);
            txtpub.setSelectedIndex(-1);
            txtcontent.setText("");
            txtno.setText("");
            txtedition.setText("");             
        }
        else
        {
            JOptionPane.showMessageDialog(this,"Error");
        }
        // TODO add your handling code here:
    } catch (SQLException ex) {
        Logger.getLogger(Book.class.getName()).log(Level.SEVERE, null, ex);
    }
}                                        
// and it gives error like this
//com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check //the manual that corresponds to your MariaDB server version for the right syntax to use near 'where id= //1' at line 1

标签: javamysqlsyntax-errormysql-error-1064mysqlupgrade

解决方案


此错误的可能原因是您编写了错误的查询。请看下面:

 pst = con.prepareStatement("update book set bname= ? , category= ? , author= ? , publisher= ? , contents= ? , pages= ? , edition= ? , where id= ? ");

版本=?, 在哪里

在 where 之前删除 ,


未来的提示,这样就不会卡在未来

  1. 尝试自己逐行调试代码并识别行号。
  2. 仔细阅读异常。
  3. 如果问题出在 SQL 中(您可以通过此处的异常名称确定MySQLSyntaxErrorException),然后首先在数据库控制台手动执行查询。

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