php - PHP：json_decode 返回 NULL（Paytm 校验和生成）

Question

我正在尝试使用 php 为 Paytm 支付网关生成校验和。

<?php

// following files need to be included
require_once("./lib/config_paytm.php");
require_once("./lib/encdec_paytm.php");

if (strcasecmp($_SERVER['REQUEST_METHOD'], 'POST') != 0) {
    throw new Exception('Request method must be POST');
}

$content = trim(file_get_contents("php://input"));


$decodeData = json_decode($content, true);
// var_dump($decodeData); // this return null

if (!empty($decodeData)) {
    $paramList = array();

    $paramList["MID"] = $decodeData["MID"]; //Provided by Paytm
    $paramList["ORDER_ID"] = $decodeData["ORDER_ID"]; //unique OrderId for every request
    $paramList["CUST_ID"] = $decodeData["CUST_ID"]; // unique customer identifier 
    $paramList["INDUSTRY_TYPE_ID"] = $decodeData["INDUSTRY_TYPE_ID"]; //Provided by Paytm
    $paramList["CHANNEL_ID"] = $decodeData["CHANNEL_ID"]; //Provided by Paytm
    $paramList["TXN_AMOUNT"] = $decodeData["TXN_AMOUNT"]; // transaction amount
    $paramList["WEBSITE"] = $decodeData["WEBSITE"]; //Provided by Paytm
    $paramList["CALLBACK_URL"] = $decodeData["CALLBACK_URL"]; //Provided by Paytm
    // $paramList["EMAIL"] = $decodeData["MID"]; // customer email id
    $paramList["MOBILE_NO"] = $decodeData["MOBILE_NO"]; // customer 10 digit mobile no.


    $checkSum = getChecksumFromArray($paramList, PAYTM_MERCHANT_KEY);

    if (!empty($checkSum)) {
        echo json_encode(array("CHECKSUMHASH" => $checkSum));
    } else {
        echo json_encode(array("ORDER_ID" => $decodeData["ORDER_ID"]));
    }
} else {
    echo "Something went wrong";
}

if (!is_array($decodeData)) {
    throw new Exception(('Recieved content containes invalid JSON'));
}

结果是json_decode回报NULL。即$decodeData是NULL。Tho$content返回正确的细节。

需要指出的一件事是$content包含PAYTM_MERCHANT_KEY 具有特殊字符（如 @ 和 %）的包含。这 json_decode是无法解码数据的原因吗？

还是我的代码有问题？

标签： phpjsonpaytm