python-3.x - 求和之谜看到重复值

Question

• 列出我们得到重复值的输出 (3,20,7)
• 如何删除重复的值？
• 有没有更简单的方法来解决这个问题？

    def riddle(x):
        list=[]
        i=0
        for i in range(0,len(x)):
            for j in range(i,len(x)):
                for k in range(j,len(x)):
                    if ((x[i]+x[j]+x[k]) ==30) and x[i]!=x[j]!=x[k]:
                        list.append((x[i],x[j],x[k]))
                        i = i+1
                        j= j+1
                        k = k+1
        return(list)

    print(riddle(x))
    x= [2,3,5,8,6,89,20,15,7]

标签： python-3.x

Answer 1

def riddle(x):
    ls = []
    for i in range(len(x)):
            for j in range(i+1,len(x)):
                for k in range(j+1,len(x)):
                    u = x[i]+x[j]+x[k]
                    if u==30:
                        ls.append([x[i],x[j],x[k]])
    return ls

x = [2,3,5,8,6,89,20,15,7]
 riddle(x)
Out[58]: [[2, 8, 20], [3, 20, 7], [8, 15, 7]]