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c - 并排打印两个金字塔（ASCII 图形）

问题描述

我可以破解它直到@symbol，但在那之后就不行了。

我不知道并排实现两个金字塔的逻辑。

int main()
    {
        int i, space, n, j, l, k=0;

        printf("Enter number excluding 1 and -ve numbers: ");
        scanf("%d",&n);

        for(i=1; i<=n-1; ++i, k=0)
        {
            for(j=0;j<(n/2);j++)
            {
                printf("\t");
            }
            for(space=1; space<=n-i; ++space)
            {
                printf("  ");
            }

            while(k != 2*i-1)
            {
                printf("* ");
                ++k;
            }//End of upper star pyramid 
            printf("\n");
        }

       //logic for @
        for(j=1;j<=(n-1);j++)
            {
                  for(l=0;l<(n/2);l++)
                {
                    printf("\t");
                }
                for(l=1; l<space; ++l)
                {
                    printf("  ");
                }
                printf("@");
                for(l=1; l<=n; l++)
                {
                    printf(" ");
                }
                printf("@\n");
            }
        //after that I dont know how to work with two different pyramids side by side
        return 0;
    }

样本

标签： c

解决方案

这是一个尝试...

已使用“#define”作为要打印的字符。

使用了三个 do-while 循环来中断打印顶部金字塔、“@”和底部金字塔的任务。

该解决方案适用于提供的示例或用户提供的任何“奇数”数字。

对于偶数，需要研究解决方案（无论哪种方式，金字塔的顶部都不会与偶数的中心对齐）。

希望这会有所帮助.....随意使用代码....

#include <stdio.h>

#define SPACE ' '
#define STAR '*'
#define AT '@'


int main(){

  int num = 7;//input from the user, have used 7 as an example

  int total_hor_length = num * 3;//# of characters to be printed on each line
  int i = num;
  int j = 0;
  while(i > 0){//calculate the iterations
    j++;        //required for top and bottom
    i -= 2;     //Pyramids
  }
  int first_print = j; //# first loop iteration
  int last_print = first_print; //# last loop iteration
  int center_print = (num * 2 - 1)-(first_print + last_print);//# center loop
  int pos = total_hor_length/2; //position of top of center pyramid
  int count = 0;
  int k;


  i = 0;//re-initialize i for the first loop 
  //Logic for the Top Pyramid(first loop)
  do{
    for(k = 0;k < total_hor_length;++k){ //for input "n"
      if((k < pos || k > pos+count))     //by the time this loop finishes
        printf("%c",SPACE);              //pos will be "n-1"
      else                               //and count will be "n+1"
        printf("%c",STAR);
    }
    putchar('\n');
    pos--;
    count+=2;
    i++;
  }while( first_print > i);

 i = 0;//re-initialize i for the center loop 
 //Logic for the "@"s (second loop)
 do{
   for(k = 0;k < total_hor_length;++k){       //utilizing the values of "count"
     if((k == count-1 || k == (count-1)+pos)) //and pos procured from the previous 
       printf("%c",AT);                       //loop to print the "@"s
     else
       printf("%c",SPACE);
   }
   putchar('\n');
   i++;
 }while(center_print > i);

 i = 0;//re-initialize i for the center loop 
 //Logic for the Bottom Pyramids (Last loop)
 do{
   for(k = 0;k < total_hor_length;++k){                                   
     if(i == 0){
       if((k <= pos-i) || (k > pos + num + i && k < total_hor_length - i))
         printf("%c",STAR);
       else if(k == pos+1||k == pos+num) //printing the line containing
         printf("%c",AT);                // asterisk and "@" symbols
       else
         printf("%c",SPACE);
     }
    else{
      if((k >= i && k <= pos-i) || (k > pos + num + i && k < total_hor_length - i))
       printf("%c",STAR);    //printing the last lines
      else
       printf("%c",SPACE);
    }
  }
     putchar('\n');
     i++;
 }while(i < last_print);

}

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