java - 为什么每次执行或进入 #3 菜单时我的 #3 菜单都没有显示
问题描述
我的输出代码有一些问题。当我运行它时,我的#3 菜单根本没有显示。只有#1 和#2 菜单。当我输入#3 时,它会显示我的#2 菜单。
注意:#2 菜单与#1 菜单的编码相同
这是我的代码:
public static void main(String[] args) throws IOException {
// TODO code application logic here
BufferedReader dataIn = new BufferedReader(new InputStreamReader(System.in));
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int foods = 1, drinks = 2, dessert = 3;
double sw = 10.00;
double bg = 15.00;
double rm = 25.00;
double it = 20.00;
double ck = 15.00;
double cf = 13.00;
double brn = 10.00;
double dnt = 15.00;
double payment, change;
System.out.println(" ******* Menu ******* ");
System.out.println("[1]Food [2]Drinks [3]Desserts");
System.out.println("Enter Choice: ");
foods=Integer.parseInt(dataIn.readLine());
if (foods == 1) {
String choice1;
System.out.println(" [a] Sandwich - 10.00 \n [b] Burger - 15.00 \n [c] Rice Meal - 25.00");
System.out.println("\n Enter Choice: ");
System.out.flush();
choice1 = br.readLine();;
if (choice1.equals("a")) {
System.out.println("You Chose a, Sandwich (10.00)");
System.out.println("Enter Payment: ");
payment=Double.parseDouble(dataIn.readLine());
if (payment < 10) {
System.out.println("Insufficient Funds");
}else{
change = payment - sw;
System.out.println("Your Change is: "+change);
System.out.println("Thank You!");
}
}
else if (choice1.equalsIgnoreCase("b")) {
System.out.println("You Chose e, Burger (15.00)");
System.out.println("Enter Payment: ");
payment=Double.parseDouble(dataIn.readLine());
if (payment < 15) {
System.out.println("Insufficient Funds");
}else{
change = payment - bg;
System.out.println("Your Change is: "+change);
System.out.println("Thank You!");
}
}
else if (choice1.equalsIgnoreCase("c")) {
System.out.println("You Chose c, Rice Meal (25.00)");
System.out.println("Enter Payment: ");
payment=Double.parseDouble(dataIn.readLine());
if (payment < 13) {
System.out.println("Insufficient Funds");
}else{
change = payment - rm;
System.out.println("Your Change is: "+change);
System.out.println("Thank You!");
}
}
} else if(dessert == 3) {
String choice3;
System.out.println(" [g] brownies - 10.00 \n [h] donuts - 15.00");
System.out.println("\n Enter Choice: ");
System.out.flush();
choice3 = br.readLine();
if (choice3.equals("g")){
System.out.println("You Chose g, brownies (10.00)");
System.out.println("Enter Payment: ");
payment=Double.parseDouble(dataIn.readLine());
if(payment < 10) {
System.out.println("Insufficient Funds");
}else{
change = payment - brn;
System.out.println("Your Change is: "+change);
System.out.println("Thank You!");
}
}
}
}
我在这里错过了什么吗?我一直在想一些东西来补偿这个程序并在 4 天内完成它。
解决方案
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