c# - Change a buttons action by two other buttons. C#

Question

I got three buttons. And have two List strings with random lines. I want to be able to push the two first buttons to change the "action" on the third one. If I click on the first button the third one only uses "HEB" and if I click the second one, the third one uses "HEC"

When pressing button1, I want button3 to do this:

HEB f1 = new HEB();
textBox1.Text = f1.RandomString();

When pressing button2, I want button3 to do this:

HEC f2 = new HEC();
textBox1.Text = f2.RandomString();

What is the best way to solve this?

EDIT: HEB and HEC are random text that is displayed in textbox1 when clicked on button3.

FULL CODE:

    namespace Questions
{
    public partial class Form1 : Form
    {

    public Form1()
    {
        InitializeComponent();
    }

    private void Form1_Load(object sender, EventArgs e)
    {

    }

    private void textBox1_TextChanged(object sender, EventArgs e)
    {

    }

    private void button1_Click(object sender, EventArgs e)
    {

        HEB f1 = new HEB();
        textBox1.Text = f1.RandomString();
    }

    private void button2_Click(object sender, EventArgs e)
    {
        HEC f2 = new HEC();
        textBox1.Text = f2.RandomString();
    }

    private void button3_Click(object sender, EventArgs e)
    {

        }
    }
}


public class HEB
{
    List<string> list = new List<string>
        {
    "This is test number 1",
    "This is test number 2",
    "This is test number 3"
    };
    public string RandomString()
    {
        Random r = new Random();
        int index = r.Next(list.Count);
        string randomString = list[index];
        return randomString;
    }
}


public class HEC
{
    List<string> list = new List<string>
        {
         "This will show later number 4",
         "This will show later number 5",
         "This will show later number 6",
};
    public string RandomString()
    {
        Random r = new Random();
        int index = r.Next(list.Count);
        string randomString = list[index];
        return randomString;
    }
}

标签： c#buttonaction

Answer 1

您可以拥有一个包含当前“消息”的列表，您可以使用前两个按钮将其更改为预定义值，然后在按下第三个按钮时随机选择一条当前消息。

就像是：

public partial class Form1 : Form
{

    private List<string> messages;

    private string RandomString()
    {
        Random random = new Random();
        return messages[random.Next(messages.Count)];
    }

//To use it just do:
//(if it is a button it should have a method that it triggers on use)
    private void HEB() 
    {
        //same for HEC, but other strings (test 3 and 4)
        messages = new List<string>(){"test 1", "test 2"}; 
    }

    private void TheButton()
    {
        textBox1.text = RandomString();
    }
}

这应该可行，但不要害怕要求更多澄清:)

编辑：更新的有效代码（只需添加变量并将当前按钮中的代码替换为我的代码）。

namespace Test_btns
{
    public partial class Form1 : Form
    {
        private List<string> messages;
        Random random = new Random();

        private string RandomString()
        {
            return messages[random.Next(messages.Count)];
        }

        public Form1()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            messages = new List<string>() { "test 1", "test 2" };
        }

        private void button2_Click(object sender, EventArgs e)
        {
            messages = new List<string>() { "test 3", "test 4" };
        }

        private void button3_Click(object sender, EventArgs e)
        {
            textBox1.Text = RandomString();
        }

        private void textBox1_TextChanged(object sender, EventArgs e)
        {
            //not really needed for this, but the method exists.
        }
    }
}