sql-server - 如何截断计算列中的小数?
问题描述
我需要创建一个查询,以显示编辑过一本书以上的编辑的平均生产力,但他们的第一本书出版的精度为 0.01 页/天。
我现在显示了正确的列,但我需要减少列中显示的零的数量AverageProductivity
。
要显示的列是
EditorName
BookName
计算列AverageProductivity
这是表格及其列
AGENT AgentID (PK,varchar(11), not null)
AgentName (varchar(25), not null)
BOOK BookName (PK, varchar(45), not null)
Genre (varchar(25), not null)
DateOfPublication (date, not null)
NoOfPages (int, not null)
WriterID (PK, FK,, varchar(11), not null)
EditorID (FK, varchar(11), not null)
EDITOR EditorID (PK, varchar(11), not null)
EditorName (varchar(25), not null)
Mentors_EditorID (FK, varchar(11), null)
WRITER WriterID (PK, varchar(11), not null)
WriterName (varchar(25), not null)
AgentID (FK, varchar(11), not null)
样本数据
insert into BOOK (BookName, WriterID, Genre, DateOfPublication, NoOfPages, EditorID)
values ('Valley of Heroes','10','Fiction','2010-01-12',874,'20');
insert into BOOK (BookName, WriterID, Genre, DateOfPublication, NoOfPages, EditorID)
values ('The Ruler''s Return','11','Fantasy','2012-03-14',765,'22');
insert into BOOK (BookName, WriterID, Genre, DateOfPublication, NoOfPages, EditorID)
values ('eRobot','11','Fantasy','2011-04-15',264,'20');
insert into BOOK (BookName, WriterID, Genre, DateOfPublication, NoOfPages, EditorID)
values ('An Uncle''s Letters','12','Fiction','2012-06-12',258,'20');
insert into BOOK (BookName, WriterID, Genre, DateOfPublication, NoOfPages, EditorID)
values ('Pretty flowers','13','Album','2013-01-31',148,'22');
insert into BOOK (BookName, WriterID, Genre, DateOfPublication, NoOfPages, EditorID)
values ('A Tale of Lions','12','Fantasy','2012-08-17',301,'21');
insert into BOOK (BookName, WriterID, Genre, DateOfPublication, NoOfPages, EditorID)
values ('eRobot','13','Sci Fi','2012-10-04',465,'23');
我尝试使用格式语法来更改精度,但我不确定它的正确语法。
这是查询...
use SignumLibri_01
select * from (
select e.EditorName, b.BookName,
round(NoOfPages * 1.0
/ datediff(day, lag(b.DateOfPublication)
over (partition by b.EditorID
order by b.DateOfPublication
)
,DateOfPublication
)
, 2) AverageProductivity
from book b
inner join editor e on e.EditorID = b.EditorID
) x
where AverageProductivity is not null
有没有办法截断所有额外的零,所以我必须达到 0.00 的精度?
结果...
Melanie eRobot 0.580000000000
Melanie An Uncle's Letters 0.610000000000
George Pretty flowers 0.460000000000
解决方案
您需要将数据类型更改为DECIMAL(X, 2)
. 该ROUND
函数实际上并不更改数据类型,只是截断或舍入特定位置的值。
CONVERT(
DECIMAL(10, 2),
round(NoOfPages * 1.0 /datediff(
day,
lag(b.DateOfPublication) over(partition by b.EditorID order by b.DateOfPublication),
DateOfPublication),
2))
另请注意,在转换为 时DECIMAL
,该值会自动四舍五入,因此您实际上不必调用该ROUND
函数(除非您想截断小数)。
;WITH ValueWithDecimals AS
(
SELECT
Value = 50 * 1.0 / 19
)
SELECT
Original = V.Value,
RoundedAt2 = ROUND(V.Value, 2),
RoundedAt4 = ROUND(V.Value, 4),
ConvertedToDecimal2 = CONVERT(DECIMAL(10, 2), V.Value),
ConvertedToDecimal4 = CONVERT(DECIMAL(10, 4), V.Value)
FROM
ValueWithDecimals AS V
结果:
Original RoundedAt2 RoundedAt4 ConvertedToDecimal2 ConvertedToDecimal4
2.631578 2.630000 2.631600 2.63 2.6316
您可以看到四舍五入的值和十进制值匹配(不是在比例和精度上,而是在内容上)。
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