首页 > 解决方案 > 通知未打开 Activity onClick

问题描述

我的应用程序中有 AlarmNotification,每次出现时我都想单击它并从后台打开父 Activity/wakeup 应用程序。为什么它不起作用?它会在特定时间显示通知,因此警报部分按预期工作,但它不会在点击时执行任何操作。

首先我必须创建通知:

private fun createNotification(){
        val vibrateFreq = longArrayOf(1000, 1000, 1000, 1000, 1000)
        nb = NotificationCompat.Builder(a, channelId)
            .setSmallIcon(R.drawable.logo)
            .setContentTitle(title)
            .setContentText(text)
            .setVibrate(vibrateFreq)
            .setStyle(NotificationCompat.BigTextStyle().bigText(textLong))
            .setAutoCancel(true)
    }

然后我需要注册警报以在特定时间显示通知:

private fun createAlarm(){
        val pInt = app.createAlarmPendingIntent(a, nb)
        val cal = Calendar.getInstance()
        cal.add(Calendar.MINUTE, delta)
        app.aManager.set(AlarmManager.RTC_WAKEUP, cal.timeInMillis, pInt)
    }

fun createAlarmPendingIntent(a: Activity, nb: NotificationCompat.Builder?): PendingIntent{
        val nInt = Intent(a, AlarmReceiver::class.java)
        nInt.putExtra(
            AlarmReceiver.NOTIFICATION_ID,
            AlarmNotification.NOTIFICATION_NAME
        )
        nInt.putExtra(AlarmReceiver.NOTIFICATION, nb?.build())

        val pInt = PendingIntent.getBroadcast(
            a,
            0,
            nInt,
            PendingIntent.FLAG_UPDATE_CURRENT
        )
        return pInt
    }

然后它会触发BroadcastReceiver打开通知:

class AlarmReceiver: BroadcastReceiver(){

    companion object{
        const val NOTIFICATION_ID = "20288855447-99899"
        const val NOTIFICATION = "alarmNotify"
    }

    override fun onReceive(context: Context?, intent: Intent?) {
        val notificationManager = context?.getSystemService(Context.NOTIFICATION_SERVICE) as NotificationManager

        val notification: Notification? = intent?.getParcelableExtra(NOTIFICATION)
        val id = intent?.getIntExtra(NOTIFICATION_ID, 0)
        id?.let {
            notificationManager.notify(id, notification)
        }
    }
}

标签: androidbroadcastreceiverandroid-notificationsandroid-pendingintent

解决方案


首先,您需要声明一个 Intent,例如:

Intent notificationClickIntent = new Intent("intent_id")

然后你需要像这样声明一个 Pending Intent:

PendingIntent pendingIntent = PendingIntent.getActivity(context, REQUEST_CODE, notificationClickIntent, PendingIntent.FLAG_UPDATE_CURRENT);

在您的通知构建器中添加设置 contentIntent:

NotificationCompat.Builder builder = new NotificationCompat.Builder(context, CHANNEL_ID)
                .setSmallIcon(R.drawable.ic_notification)
                .setContentTitle(notificationData.getTitle())
                .setContentText(notificationData.getBody())
                .setPriority(NotificationCompat.PRIORITY_HIGH)
                **.setContentIntent(notificationClickPendingIntent)**
                .addAction(R.drawable.ic_notification, context.getString(R.string.turn_on_alarms), notificationButtonClickPendingIntent)
                .setAutoCancel(true)

在您的清单中声明您要打开的活动的意图过滤器(因为我记得我无法使其适用于启动器活动,也许它可以工作,我只是放弃了)。

<activity
        android:name="Activity_name"
        android:launchMode="singleTask"
        android:screenOrientation="portrait"
        android:theme="@style/AppTheme.NoActionBar.LightStatusBar">
        <intent-filter>
            <action android:name="intent_id" />
            <category android:name="android.intent.category.DEFAULT" />
        </intent-filter>
    </activity>

最后但同样重要的是,如果activity没有打开,通知onClick会触发onCreate方法,如果它已经打开,会触发onNewIntent

希望这可以帮助 :)


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