首页 > 解决方案 > 在R中的数据框列表中拆分列

问题描述

我有一个数据框列表,其中某些列具有此特殊字符->(箭头)。现在我确实想遍历这个数据框列表并用这个->(箭头)定位列,然后用后缀_old和_new命名新列。这是数据帧的示例:

dput(df1)
df1 <- structure(list(v1 = c("reg->joy", "ress", "mer->dls"),
                      t2 = c("James","Jane", "Egg")),
                 class = "data.frame", row.names = c(NA,  -3L))

dput(df2)
df2 <- structure(list(v1 = c("me", "df", "kl"),
                      t2 = c("James","Jane->dlt", "Egg"),
                      t3 = c("James ->may","Jane", "Egg")),
                 class = "data.frame", row.names = c(NA,  -3L))
dput(df3)
df3 <- structure(list(v1 = c("56->34", "df23-> ", "mkl"),
                      t2 = c("James","Jane", "Egg"),
                      d3 = c("James->","Jane", "Egg")),
                 class = "data.frame", row.names = c(NA,  -3L))

这是我尝试过的

dfs <- list(df1,df2,df3)

for (y in 1:length(dfs)){
  setDT(dfs[[y]])
  df1<- lapply(names(dfs[[y]]), function(x) {
    mDT <- df2[[y]][, tstrsplit(get(x), " *-> *")]
    if (ncol(mDT) == 2L) setnames(mDT, paste0(x, c("_old", "_new")))
  }) %>% as.data.table()

}

这只会拆分一个数据帧,我需要拆分所有数据帧

预期输出


dput(df1)
df1 <- structure(list(v1_old = c("reg", "mer"),
                      v1_new = c("joy", "dls")),
                 class = "data.frame", row.names = c(NA,  -3L))

dput(df2)
df2 <- structure(list(t2_old = c("dlt"),
                      t2_new = c("dlt"),
                      t3_old = c("James"),
                      t3_new = c("may")),
                 class = "data.frame", row.names = c(NA,  -3L))

dput(df3)
df3 <- structure(list(v1_old = c("56", "df23 "),
                      v1_new = c("34", " "),
                      d3 = c("James"),
                      d3 = c(" ")),
                 class = "data.frame", row.names = c(NA,  -3L))

标签: r

解决方案


所以我玩了一圈,找到了答案

df1 <-c()
for (y in 1:length(dfs)){
  setDT(dfs[[y]])
  df1[[y]] <- lapply(names(modifiedtbl[[y]]), function(x) {
    mDT <- dfs[[y]][, tstrsplit(get(x), " *-> *")]
    if (ncol(mDT) == 2L) setnames(mDT, paste0(x, c("_old", "_new")))
  }) %>% as.data.table()

}

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