首页 > 解决方案 > sequelize 不包括 model.create 上的用户

问题描述

创建帖子时,Sequlelize 不会返回关联的用户。这是路由器。

我也参考了文档。

https://sequelize.org/master/manual/associations.html#creating-with-associations

 createPost: async (req: any, res: Response) => {
    const postData = {
      title: req.body.title,
      postContent: req.body.postContent,
      authorId: req.session.user.id
    };
    await models.Post.create(postData, {
      include: [{ model: models.User, as: "author" }]
    })
      .then(post => {
        res.status(200).send({
          message: "post created",
          post: post
        });
      })
      .catch(err => {
        res.status(401).send({
          message: `Something went wrong`,
          error: err
        });
      });
    console.log(req.body);
  }

我不确定为什么这不起作用,因为这条路线使用相应用户的用户名获取帖子

  getPosts: async (req: Request, res: Response) => {
    await models.Post.findAll({
      include: [
        { model: models.User, as: "author", attributes: ["username"] },
        { model: models.Likes }
      ],
      order: [["createdAt", "DESC"]],
      limit: 6
    }).then(posts => {
      res.json(posts);
    });
  },

这是 Post 和 User 的模型。

用户.js

"use strict";
module.exports = (sequelize, DataTypes) => {
    var User = sequelize.define("User", {
        username: DataTypes.STRING,
        password: DataTypes.STRING,
        email: DataTypes.STRING,
        forget_password: DataTypes.STRING
    });
    User.associate = function (models) {
        User.hasMany(models.Post, {
            foreignKey: "authorId",
            as: "author",
            onDelete: "CASCADE"
        });
    };
    return User;
};

Post.js

"use strict";
module.exports = (sequelize, DataTypes) => {
    var Post = sequelize.define("Post", {
        title: DataTypes.STRING,
        postContent: DataTypes.STRING,
        liked: {
            type: DataTypes.BOOLEAN,
            allowNull: false,
            defaultValue: false
        },
        likeCounts: {
            type: DataTypes.INTEGER,
            allowNull: false,
            defaultValue: 0
        },
        authorId: DataTypes.INTEGER
    });
    Post.associate = function (models) {
        Post.belongsTo(models.User, {
            as: "author",
            foreignKey: "authorId",
            onDelete: "CASCADE"
        });
        Post.hasMany(models.Likes, {
            foreignKey: "resourceId",
            timestamps: false,
            onDelete: "CASCADE",
            scope: {
                type: "article"
            }
        });
    };
    return Post;
};

标签: node.jspostgresqlsequelize.js

解决方案


这给了我想要的结果,所以这会起作用。

await models.Post.create(postData)
  .then(post => {
    models.Post.findOne({
      where: {
        id: post.id
      },
      include: [
        { model: models.User, as: "author", attributes: ["username"] },
        { model: models.Likes }
      ]
    }).then(newPost => {
      res.status(200).send({
        message: "post created",
        post: newPost
      });
    });
  })

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