首页 > 解决方案 > 使用 case 语句时的 Group By 子句问题

问题描述

我试图总结每个不同发件人全年的数量,并将年份作为字段。我正在使用 case 语句来执行此操作。

select distinct sender,
  case
    when extract(month from (month)) = 1
      then sum(volume)
  end as January,
  case
    when  extract(month from (month)) = 2
      then sum(volume)
  end as February,
  case
    when extract(month from (month)) = 3
      then sum(volume)
  end as March
from [lifetime_data]
group by 1

当我运行这个时,我收到一个错误,要求我按月分组,月份不是我选择的列之一,我只在我的情况下使用它......我该如何解决这个问题?

标签: sqlpostgresql

解决方案


我认为你想要条件聚合——case表达式是一个参数sum()

select sender,
       sum(case when extract(month from (month)) = 1 then volume end) as January,
       sum(case when extract(month from (month)) = 2 then volume end) as February,
       sum(case when extract(month from (month)) = 3 then volume end) as March
from [lifetime_data]
group by 1

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