首页 > 解决方案 > 需要为除 ir.sequence 之外的一个 sale.order 打印五个序列号

问题描述

我已经编写了代码来为 1 个销售订单打印五个序列号,但它会影响最后一个销售订单号,它正在跳跃 5 个订单号

我必须为没有 ir 序列的 1 个销售订单打印 5 个序列号

 ticket = fields.Char(string="Ticket", readonly=True, required=True, copy=False, default='New')

 @api.multi
  def action_confirm(self): 
    result = super(SaleOrder, self).action_confirm()

    len_count = []
    ticket_list = []
    tickets = ""
    count = 5
    for i in range(count):
        x = self.env['ir.sequence'].next_by_code('sale.order')
        if not len(len_count) == 5:
            if not tickets:
                tickets = x 
            else:
                tickets = tickets + ',' + x
    print tickets
    print 'abc'


    ticket_list.append(str(tickets))
    self.ticket = ticket_list
    print ticket_list
    ctx = dict(self.env.context or {})
    ctx.update({
        'sale_action_new': ticket_list,
        })    
    print ctx

    template = self.env.ref('sale_order.email_template_ticket')
    template.with_context(ctx).send_mail(self.id)

标签: odooany

解决方案


让我试着帮忙。

start = self.id               //sales-order id
limit = start + 5 
for x in range(start, limit):
   if not tickets:
      tickets = x 
   else:
       tickets = tickets + ',' + x

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