首页 > 解决方案 > Tkinter 不会在中间更新 gui,除非它完成处理休息

问题描述

我是编程和 python 的新手,请找到示例代码,这是一个井字游戏,我希望 gui 在开始处理下一帧之前更新我的“标记 x”帧。

我不知道如何使它工作,

try:
    import tkinter as tk
except:
    import Tkinter as tk
import time as t
import random as r

data_list = ['a1', 'a2', 'a3', 'a4', 'a5', 'a6', 'a7', 'a8', 'a9']
used_list = ['a1', 'a2', 'a3', 'a4', 'a5', 'a6', 'a7', 'a8', 'a9']
color = ['green yellow', 'yellow', 'green yellow', 'yellow',
         'green yellow', 'yellow', 'green yellow', 'yellow', 'green yellow']
row_col = [(0, 0), (0, 1), (0, 2), (1, 0), (1, 1), (1, 2), (2, 0), (2, 1), (2, 2)]
unused = list

mw = tk.Tk()
mw.geometry("300x300+50+50")

for i in range(3):
    mw.columnconfigure(i, weight=10)
    mw.rowconfigure(i, weight=10)

for j in range(9):
    data_list[j] = tk.Frame(mw)
    data_list[j].grid(row=row_col[j][0], column=row_col[j][1])
    data_list[j].config(background=color[j], width=100, height=100)
    data_list[j].rowconfigure(0, minsize=100)
    data_list[j].columnconfigure(0, minsize=100)
    tk.Button(data_list[j], background=color[j], border=1, command=lambda x=j: cross_mark(data_list[x])).grid(row=0, column=0, columnspan=1, rowspan=1, sticky='nsew')


def cross_mark(blk):
    tk.Button(blk, background='orange red', border=4, text='X', font='30').grid(row=0, column=0, columnspan=1, rowspan=1, sticky='nsew')
    comp_mark(blk)


def comp_mark(used):
    blk = r.choice(data_list)
    if blk == used:
        while blk == used:
            blk = r.choice(data_list)
    t.sleep(5)
    tk.Button(blk, background='RoyalBlue1', border=4, text='X', font='30').grid(row=0, column=0, columnspan=1, rowspan=1, sticky='nsew')
mw.mainloop()

请运行上面的代码,看看你能不能解决我的问题

标签: pythontkintertktic-tac-toe

解决方案


使用aftertkinter 提供的方法在一定时间后处理某个函数/回调事件。在使用 tkinter 时使用它永远不可行time.sleep,因为 tkinter 本身处于恒定等待状态(即,它正在等待按钮单击或其他事件)

cross_mark在您的函数中添加以下内容:

def cross_mark(blk):
    tk.Button(blk, background='orange red', border=4, text='X', font='30').grid(row=0, column=0, columnspan=1, rowspan=1, sticky='nsew')
    mw.update_idletasks()
    mw.after(1000, comp_mark(blk))

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