exception - Kotlin协程异常处理——如何抽象try-catch
问题描述
我试图了解 Kotlin 协程中的异常处理,所以我想出了这个非常简单的场景,其中网络调用引发异常,我的应用程序必须捕获并处理它。
如果我用 try-catch 块包围我的 async.await() 调用,它会按预期工作。但是,如果我尝试将 try-catch 抽象为扩展函数,我的应用程序就会崩溃。
我在这里想念什么?
import android.os.Bundle
import androidx.appcompat.app.AppCompatActivity
import kotlinx.coroutines.*
class Main2Activity : AppCompatActivity() {
private val job: Job = Job()
private val scope = CoroutineScope(Dispatchers.Default + job)
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_main2)
runCode()
}
private suspend fun asyncCallThrowsException(): Deferred<Boolean> =
withContext(Dispatchers.IO) {
Thread.sleep(3000)// simulates a blocking request/response (not on the Main thread, though)
throw(Exception())
}
suspend fun <T> Deferred<T>.awaitAndCatch() {
try {
this.await()
} catch (e: Exception) {
println("exception caught inside awaitAndCatch")
}
}
private fun runCode() {
scope.launch {
//This block catches the exception.
try {
val resultDeferred = asyncCallThrowsException()
resultDeferred.await()
} catch (e: Exception) {
println("exception caught inside try-catch")
}
//This line does not, and crashes my app.
asyncCallThrowsException().awaitAndCatch()
}
}
}
编辑:我实际上忘记将调用包装在一个async
块内。现在,即使是显式的 try-catch 块也不起作用......
import android.os.Bundle
import androidx.appcompat.app.AppCompatActivity
import kotlinx.coroutines.*
class Main4Activity : AppCompatActivity() {
private val job: Job = Job()
private val scope = CoroutineScope(Dispatchers.Default + job)
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_main)
runCode()
}
private suspend fun callThrowsException(): String =
withContext(Dispatchers.IO) {
Thread.sleep(3000)// simulates a blocking request/response (not on the Main thread, though)
throw(Exception())
"my result"
}
suspend fun <T> Deferred<T>.awaitAndCatch(): T? {
try {
return this.await()
} catch (e: Exception) {
println("exception caught inside awaitAndCatch")
}
return null
}
private fun runCode() {
scope.launch {
val resultDeferred: Deferred<String> = async { callThrowsException() }
var result: String?
// This doesn't catch the throwable, and my app crashes - but the message gets printed to the console.
try {
result = resultDeferred.await()
} catch (e: Exception) {
println("exception caught inside try-catch")
}
// This doesn't catch the throwable, and my app crashes - but the message gets printed to the console.
result = resultDeferred.awaitAndCatch()
}
}
}
解决方案
问题与您如何捕获异常无关。问题是,当您的异步作业失败(抛出异常)时,它会取消您为活动所做的作业。
即使您的代码可以捕获异常并打印消息,父作业也会尽快终止。
而不是像这样:val: Job = Job()
,尝试val: Job = SupervisorJob()
当其子项失败时,主管作业不会被取消,因此这不会使您的应用程序崩溃。
或者,如果您想要一种方法来启动没有此问题的异步作业,请参阅:Safe async in a given scope
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