python - 如何从私钥中获取椭圆曲线公钥

Question

因此，我需要使用 ECC spec256k1 从相应的 256 位数字中获取公钥。

因此，假设我使用 sha256 从任何密码中获取私钥，如下所示：

>>> import hashlib
>>> private_key = hashlib.sha3_256(b"Led Zeppelin - No Quarter").hexdigest()
>>> private_key
'c0b279f18074de51d075b152c8ce78b7bddb284e8cfde19896162abec0a0acce'

如何从该私钥中获取公钥？我需要将公钥打印为字符串。

标签： pythonpublic-key-encryptionelliptic-curveecdsa

Answer 1

pip install fastecdsa

from fastecdsa import keys, curve,ecdsa
priv_key, pub_key = keys.gen_keypair(curve.secp256k1) 

print(pub_key)

产生

X: 0xcc228e1a4c8e187a0deeabcd6e43bc8f7b6bdd91b8f823912f2de188fba054e6
Y: 0x7995a9d3866a8fa11a9af933c76216a908995ec5cec6ed7d3056b787fa7d39d7

支持的原语

素数场上的曲线-源

Name                      Class

P192 / secp192r1          fastecdsa.curve.P192  
P224 / secp224r1          fastecdsa.curve.P224  
P256 / secp256r1          fastecdsa.curve.P256  
P384 / secp384r1          fastecdsa.curve.P384  
P521 / secp521r1          fastecdsa.curve.P521 
secp192k1                 fastecdsa.curve.secp192k1     
secp224k1                 fastecdsa.curve.secp224k1     
secp256k1 (bitcoin curve) fastecdsa.curve.secp256k1     
brainpoolP160r1           fastecdsa.curve.brainpoolP160r1   
brainpoolP192r1           fastecdsa.curve.brainpoolP192r1   
brainpoolP224r1           fastecdsa.curve.brainpoolP224r1   
brainpoolP256r1           fastecdsa.curve.brainpoolP256r1   
brainpoolP320r1           fastecdsa.curve.brainpoolP320r1   
brainpoolP384r1           fastecdsa.curve.brainpoolP384r1
brainpoolP512r1           fastecdsa.curve.brainpoolP512r1