c - 指针和/或函数无法正常工作

问题描述

尝试运行此代码将显示大多数字段的空白输入并且会混淆，例如街道号码将代替名字。不知道发生了什么。起初对使用 stackoverflow 犹豫不决，但现在看来我别无选择

头文件：

// Structure type Name declaration
struct Name {
    char firstName[31];
    char middleInitial[7];
    char lastName[36];
};

// Structure type Address declaration
struct Address {
    int streetNumber;
    char street[41];
    int apartmentNumber;
    char postalCode[8];
    char city[41];
};


// Structure type Numbers declaration
struct Numbers {
    char cell[11];
    char home[11];
    char business[11];
};


// Structure type Contact declaration
struct Contact {
    struct Name name;
    struct Address address;
    struct Numbers numbers;
};


//------------------------------------------------------
// Function Prototypes
//------------------------------------------------------

// Get and store from standard input the values for Name
void getName(struct Name* name);


// Get and store from standard input the values for Address
void getAddress(struct Address* address);


// Get and store from standard input the values for Numbers
void getNumbers(struct Numbers* numbers);

输入文件


#define _CRT_SECURE_NO_WARNINGS

#include <stdio.h>
#include "contacts.h"

//This function will clear the input buffer after every input
void clear() {
    while (getchar() != '\n');
}


// Get and store from standard input the values for Name
void getName(struct Name* name) {

    char option = 0;

    printf("Please enter the contact's first name: ");
    scanf("%31s", name[0].firstName);
    clear();

    printf("Do you want to enter a middle initial(s)? (y or n): ");
    scanf("%c", &option);
    clear();

    if (option == 'y' || option == 'Y') {
        printf("Please enter the contact's middle initial(s): ");
        scanf("%7[^\n]s", name[0].middleInitial);
        clear();
    }

    printf("Please enter the contact's last name: ");
    scanf("%36[^\n]s", name[0].lastName);
    clear();
}


// Get and store from standard input the values for Address
void getAddress(struct Address* address) {

    char option = 0;

    printf("Please enter the contact's street number: ");
    scanf("%d", &address[0].streetNumber);
    clear();

    printf("Please enter the contact's street name: ");
    scanf("%40[^\n]s", address[0].street);
    clear();

    printf("Do you want to enter an apartment number? (y or n): ");
    scanf("%c", &option);
    clear();

    if (option == 'y' || option == 'Y') {
        printf("Please enter the contact's apartment number: ");
        scanf("%d", &address[0].apartmentNumber);
        clear();
    }

    printf("Please enter the contact's postal code: ");
    scanf("%7[^\n]s", address[0].postalCode);
    clear();

    printf("Please enter the contact's city: ");
    scanf("%40[^\n]s", address[0].city);
    clear();
}


// Get and store from standard input the values for Numbers
void getNumbers(struct Numbers* numbers) {

    char option = 0;

    printf("Do you want to enter a cell phone number? (y or n): ");
    scanf("%c", &option);
    clear();

    if (option == 'y' || option == 'Y') {
        printf("Please enter the contact's cell phone number: ");
        scanf("%11s", numbers[0].cell);
        clear();
    }

    printf("Do you want to enter a home phone number? (y or n): ");
    scanf("%c", &option);
    clear();

    if (option == 'y' || option == 'Y') {
        printf("Please enter the contact's home phone number: ");
        scanf("%11s", numbers[0].home);
        clear();
    }

    printf("Do you want to enter a business phone number? (y or n): ");
    scanf("%c", &option);
    clear();

    if (option == 'y' || option == 'Y') {
        printf("Please enter the contact's business phone number: ");
        scanf("%11s", numbers[0].business);
        clear();
    }
}

我的主要程序：

#define _CRT_SECURE_NO_WARNINGS

#include <stdio.h>
#include "contacts.h"


int main(void)
{

    // Declare variables:
    struct Contact contact[] = {{0}};


        // Display the title
        printf("Contact Management System\n");
        printf("-------------------------\n");


        // Call the Contact function getName to store the values for the Name member
        getName(contact);

        // Call the Contact function getAddress to store the values for the Address member
        getAddress(contact);

        // Call the Contact function getNumbers to store the values for the Numbers member
        getNumbers(contact);

    // Display Contact summary details
    printf("\n");
    printf("Contact Details\n");
    printf("===============\n");
    printf("Name Details\n");
    printf("------------\n");
    printf("First name: %s\n", contact[0].name.firstName);
    printf("Middle initial(s): %s\n", contact[0].name.middleInitial);
    printf("Last name: %s\n", contact[0].name.lastName);
    printf("\n");
    printf("Address Details\n");
    printf("--------------\n");
    printf("Street number: %d\n", contact[0].address.streetNumber);
    printf("Street name: %s\n", contact[0].address.street);
    printf("Apartment: %d\n", contact[0].address.apartmentNumber);
    printf("Postal code: %s\n", contact[0].address.postalCode);
    printf("City: %s\n", contact[0].address.city);
    printf("\n");
    printf("Phone Numbers\n");
    printf("-------------\n");
    printf("Cell phone number: %s\n", contact[0].numbers.cell);
    printf("Home phone number: %s\n", contact[0].numbers.home);
    printf("Business phone number: %s\n", contact[0].numbers.business);
    printf("\n");


    // Display Completion Message
    printf("Structure test for Contact using functions done!\n");

    return 0;

}

任何帮助将不胜感激，谢谢

标签： cfunctionpointers

c - 指针和/或函数无法正常工作

问题描述

解决方案

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