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php - ORDER BY 和 WHERE 变量和 LIMIT

问题描述

我有一个带有以下 SQL 代码的变量，它给了我一个错误（没有“ORDER BY name ASC”，代码可以正常工作）：

$sql = "SELECT * FROM incidents WHERE active = 1 AND username = '".$_SESSION['username']."' LIMIT " . $limitNumber . "," . $pageCounter " ORDER BY name ASC";

给出下一个错误：

解析错误：语法错误，意外 '" ORDER BY name ASC"' (T_CONSTANT_ENCAPSED_STRING) in...

有什么想法可以解决这个问题吗？

问候。

编辑：

出于上下文目的共享所有代码：

<?php

include 'includes/dbh.inc.php';
include 'user_session.php';

// Limit quantity of results per page

$pageCounter = 10;

// Show number of rows in the table

$sql = "SELECT * FROM incidents WHERE active = 1 AND username = '".$_SESSION['username']."'";
$result = mysqli_query($conn, $sql);
$rowNumbers = mysqli_num_rows($result);

//while ($row = mysqli_fetch_array($result)) {
//  echo $row['id'] . " " . $row['username'] . " " . $row['phone'] . "<br>";
//}

// Number of pages available

$numberPages = ceil($rowNumbers/$pageCounter);

// Determine in which page is the user

if (!isset($_GET['page'])) {
    $page = 1;
} else {
    $page = $_GET['page'];
}

// Determine limit per page

$limitNumber = ($page-1)*$pageCounter;

// Show results

$sql = "SELECT * FROM incidents WHERE active = 1 AND username = '".$_SESSION['username']."' LIMIT " . $limitNumber . "," . $pageCounter " ORDER BY name ASC";
$result = mysqli_query($conn, $sql);

echo "<table>";
 echo "<tr><th>Name</th><th>TMC Location</th><th>Non-TMC Location</th><th>Country Code</th><th>Origin Offset</th><th>To Offset</th><th>Start Time</th><th>End Time</th><th>Updated</th><th>Created</th><th>AlertC</th><th>Note</th><th>Group</th><th>Action</th><th>Worked By</th><th>Date</th><th>Incident ID</th><th>Username</th><th>Edit</th><th>Delete</th></tr>";

while ($row = mysqli_fetch_array($result)) {
    $id = $row['id'];
    $name = $row['name'];
    $tmclocation = $row['tmclocation'];
    $nontmclocation = $row['nontmclocation'];
    $countrycode = $row['countrycode'];
    $ooffset = $row['ooffset'];
    $toffset = $row['toffset'];
    $stime = $row['stime'];
    $etime = $row['etime'];
    $updated = $row['updated'];
    $created = $row['created'];
    $alertc = $row['alertc'];
    $rcoby = $row['rcoby'];
    $note = $row['note'];
    $rcogroup = $row['rcogroup'];
    $action = $row['action'];
    $workedby = $row['workedby'];
    $date = $row['rcodate'];
    $username = $row['username'];
    $incidentid = $row['incidentid'];
  echo "<tr><td>".$name."</td><td>".$tmclocation."</td><td>".$nontmclocation."</td><td>".$countrycode."</td><td>".$ooffset."</td><td>".$toffset."</td><td>".$stime."</td><td>".$etime."</td><td>".$updated."</td><td>".$created."</td><td>".$alertc."</td><td>".$note."</td><td>".$rcogroup."</td><td>".$action."</td><td>".$workedby."</td><td>".$date."</td><td>".$incidentid."</td><td>".$username."</td><td><a href='myincidents.php?id=" . $row['id'] ."'>Edit</a></td><td><a id='a_id' href='editor/delete.php?id=" . $row['id'] ."' onClick='return confirm(\"Are you sure?\");'>Delete</a></td></tr>";
}

echo "</table>";

// Display number of pages

for ($page=1; $page <= $numberPages ; $page++) { 
    echo '<a href="myincidents.php?page=' . $page . '">' . $page . ' </a>';
}

?>

标签： phpmysqlsql

解决方案

order by首先在做之前limit。

$sql = "SELECT * FROM incidents WHERE active = 1 AND username = '".$_SESSION['username']."' ORDER BY name ASC LIMIT " . $limitNumber . "," . $pageCounter " ";

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